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Of the following vector fields, the one that is conservative corresponds to: 3ху1+х A) F(x, y, z) = (x³, 3y¹+x, =¹+²) 3ху1+z B) F(x, y, z) = (y³, 3y¹+²=²+2) 3r*y+z C) F(x, y, z) = (y³, +六) y² D) F(x, y, z) = (x³, = (x³, 3a¹4u+², ÷ +12)

Of the following vector fields, the one that is conservative corresponds to: 3ху1+х A) F(x, y, z) = (x³, 3y¹+x, =¹+²) 3ху1+z B) F(x, y, z) = (y³, 3y¹+²=²+2) 3r*y+z C) F(x, y, z) = (y³, +六) y² D) F(x, y, z) = (x³, = (x³, 3a¹4u+², ÷ +12)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Of the following vector fields, the one that is conservative corresponds to: 3ху1+х A) F(x, y, z) = (x³, 3y¹+x, =¹+²) 3ху1+z B) F(x, y, z) = (y³, 3y¹+²=²+2) 3r*y+z C) F(x, y, z) = (y³, +六) y² D) F(x, y, z) = (x³, = (x³, 3a¹4u+², ÷ +12)
Transcribed Image Text:Of the following vector fields, the one that is conservative corresponds to: 3ху1+х A) F(x, y, z) = (x³, 3y¹+x, =¹+²) 3ху1+z B) F(x, y, z) = (y³, 3y¹+²=²+2) 3r*y+z C) F(x, y, z) = (y³, +六) y² D) F(x, y, z) = (x³, = (x³, 3a¹4u+², ÷ +12)
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