Of the following vector fields, the one that is conservative corresponds to: 3ху1+х A) F(x, y, z) = (x³, 3y¹+x, =¹+²) 3ху1+z B) F(x, y, z) = (y³, 3y¹+²=²+2) 3r*y+z C) F(x, y, z) = (y³, +六) y² D) F(x, y, z) = (x³, = (x³, 3a¹4u+², ÷ +12)

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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Of the following vector fields, the one that is conservative corresponds to:
3ху1+х
A) F(x, y, z) = (x³, 3y¹+x, =¹+²)
3ху1+z
B) F(x, y, z) = (y³,
3y¹+²=²+2)
3r*y+z
C) F(x, y, z) = (y³,
+六)
y²
D) F(x, y, z) = (x³,
= (x³, 3a¹4u+², ÷ +12)
Transcribed Image Text:Of the following vector fields, the one that is conservative corresponds to: 3ху1+х A) F(x, y, z) = (x³, 3y¹+x, =¹+²) 3ху1+z B) F(x, y, z) = (y³, 3y¹+²=²+2) 3r*y+z C) F(x, y, z) = (y³, +六) y² D) F(x, y, z) = (x³, = (x³, 3a¹4u+², ÷ +12)
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