**Educational Website Content:** --- ### Vector Projections Exercise **Problem Statement:** Given two vectors in a 2-dimensional space: \[ \mathbf{v} = 3\mathbf{i} + \mathbf{j} \] \[ \mathbf{w} = -3\mathbf{i} - \mathbf{j} \] Determine the projection of \(\mathbf{v}\) onto \(\mathbf{w}\). **Question:** If \(\mathbf{v} = 3\mathbf{i} + \mathbf{j}\) and \(\mathbf{w} = -3\mathbf{i} - \mathbf{j}\), then the projection of \(\mathbf{v}\) onto \(\mathbf{w}\) is: - \(\mathbf{A.} \ -3\mathbf{i} - \mathbf{j}\) - \(\mathbf{B.} \ 3\mathbf{i} + \mathbf{j}\) - \(\mathbf{C.} \ 2\mathbf{i} + 3\mathbf{j}\) - \(\mathbf{D.} \ -2\mathbf{i} - 3\mathbf{j}\) --- **Solution Explanation:** To find the projection of \(\mathbf{v}\) onto \(\mathbf{w}\), use the formula: \[ \text{proj}_\mathbf{w}\mathbf{v} = \left(\frac{\mathbf{v} \cdot \mathbf{w}}{\mathbf{w} \cdot \mathbf{w}}\right) \mathbf{w} \] Where \(\mathbf{v} \cdot \mathbf{w}\) is the dot product of \(\mathbf{v}\) and \(\mathbf{w}\), and \(\mathbf{w} \cdot \mathbf{w}\) is the dot product of \(\mathbf{w}\) with itself. 1. Calculate the dot product \(\mathbf{v} \cdot \mathbf{w}\): \[ \mathbf{v} \cdot \mathbf{w} = (3)(-3) + (1)(-1) = -9 - 1 = -10 \] 2. Calculate the dot product \(\mathbf{w} \cdot \mathbf{w}\): \[ \mathbf{w} \cdot \mathbf{w} = (-3)^2

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Chapter1: Functions And Models
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**Educational Website Content:**

---

### Vector Projections Exercise

**Problem Statement:**

Given two vectors in a 2-dimensional space:

\[ \mathbf{v} = 3\mathbf{i} + \mathbf{j} \]

\[ \mathbf{w} = -3\mathbf{i} - \mathbf{j} \]

Determine the projection of \(\mathbf{v}\) onto \(\mathbf{w}\).

**Question:**

If \(\mathbf{v} = 3\mathbf{i} + \mathbf{j}\) and \(\mathbf{w} = -3\mathbf{i} - \mathbf{j}\), then the projection of \(\mathbf{v}\) onto \(\mathbf{w}\) is:

- \(\mathbf{A.} \ -3\mathbf{i} - \mathbf{j}\)
- \(\mathbf{B.} \ 3\mathbf{i} + \mathbf{j}\)
- \(\mathbf{C.} \ 2\mathbf{i} + 3\mathbf{j}\)
- \(\mathbf{D.} \ -2\mathbf{i} - 3\mathbf{j}\)

---

**Solution Explanation:**
To find the projection of \(\mathbf{v}\) onto \(\mathbf{w}\), use the formula:

\[ \text{proj}_\mathbf{w}\mathbf{v} = \left(\frac{\mathbf{v} \cdot \mathbf{w}}{\mathbf{w} \cdot \mathbf{w}}\right) \mathbf{w} \]

Where \(\mathbf{v} \cdot \mathbf{w}\) is the dot product of \(\mathbf{v}\) and \(\mathbf{w}\), and \(\mathbf{w} \cdot \mathbf{w}\) is the dot product of \(\mathbf{w}\) with itself.

1. Calculate the dot product \(\mathbf{v} \cdot \mathbf{w}\):

\[ \mathbf{v} \cdot \mathbf{w} = (3)(-3) + (1)(-1) = -9 - 1 = -10 \]

2. Calculate the dot product \(\mathbf{w} \cdot \mathbf{w}\):

\[ \mathbf{w} \cdot \mathbf{w} = (-3)^2
Transcribed Image Text:**Educational Website Content:** --- ### Vector Projections Exercise **Problem Statement:** Given two vectors in a 2-dimensional space: \[ \mathbf{v} = 3\mathbf{i} + \mathbf{j} \] \[ \mathbf{w} = -3\mathbf{i} - \mathbf{j} \] Determine the projection of \(\mathbf{v}\) onto \(\mathbf{w}\). **Question:** If \(\mathbf{v} = 3\mathbf{i} + \mathbf{j}\) and \(\mathbf{w} = -3\mathbf{i} - \mathbf{j}\), then the projection of \(\mathbf{v}\) onto \(\mathbf{w}\) is: - \(\mathbf{A.} \ -3\mathbf{i} - \mathbf{j}\) - \(\mathbf{B.} \ 3\mathbf{i} + \mathbf{j}\) - \(\mathbf{C.} \ 2\mathbf{i} + 3\mathbf{j}\) - \(\mathbf{D.} \ -2\mathbf{i} - 3\mathbf{j}\) --- **Solution Explanation:** To find the projection of \(\mathbf{v}\) onto \(\mathbf{w}\), use the formula: \[ \text{proj}_\mathbf{w}\mathbf{v} = \left(\frac{\mathbf{v} \cdot \mathbf{w}}{\mathbf{w} \cdot \mathbf{w}}\right) \mathbf{w} \] Where \(\mathbf{v} \cdot \mathbf{w}\) is the dot product of \(\mathbf{v}\) and \(\mathbf{w}\), and \(\mathbf{w} \cdot \mathbf{w}\) is the dot product of \(\mathbf{w}\) with itself. 1. Calculate the dot product \(\mathbf{v} \cdot \mathbf{w}\): \[ \mathbf{v} \cdot \mathbf{w} = (3)(-3) + (1)(-1) = -9 - 1 = -10 \] 2. Calculate the dot product \(\mathbf{w} \cdot \mathbf{w}\): \[ \mathbf{w} \cdot \mathbf{w} = (-3)^2
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