Calculus Question

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Step 1

Given information: The gardener has 680ft of fencing on three sides of the garden.

Calculation:

Consider L as the length of the garden and as the breadth of the rectangle.

 Use the formula of the perimeter of rectangle and given figure.

The perimeter of the garden would be L+2W=680.

Therefore, the length of the garden can be find as,

L+2W=680L=680-2W

 

 

 

Step 2

The area of the rectangle is A=LW

Now find the area of the rectangular garden the formula of the area of the rectangle.

A=680-2WW=680W-2W2=-2W2+680W

Compare the equation -2W2+680W with the equation ax2+bx+c.

It can be seen that the above equation is the quadratic equation. The graph of the quadratic equation is the parabola.

The vertex of the parabola determines the maximum and minimum points of the parabola.

If the coefficient of x2 is positive then the vertex is the minimum point and if the the coefficient of x2 is negative then the vertex is the maximum point

The coefficient of W2 is negative for the equation -2W2+680W.

Therefore, the vertex of the equation leads to greatest area of the rectangular garden.

 

 

 

 

 

 

Step 3

The vertex h,k of the equation ax2+bx+c where the value of h=-b2a and fh=k.

In the equation -2W2+680W, the value of W for the maximum area can be find as,

W=-680-22W=170 ft

Find the value of L=680-2W.

L=680-2170=680-340=340 ft

 

 

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