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S For x1/2 dx and using the substitution = x1/2, the resulting integral takes the form: x-x3 -du S- S- S- S- U 1-u4 4u 4-u² 4u (24²) 2 -du 4- u -du -du

S For x1/2 dx and using the substitution = x1/2, the resulting integral takes the form: x-x3 -du S- S- S- S- U 1-u4 4u 4-u² 4u (24²) 2 -du 4- u -du -du

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.4: Complex And Rational Zeros Of Polynomials
Problem 14E
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S For x1/2 dx and using the substitution = x1/2, the resulting integral takes the form: x-x3 -du S- S- S- S- U 1-u4 4u 4-u² 4u (24²) 2 -du 4- u -du -du
Transcribed Image Text:S For x1/2 dx and using the substitution = x1/2, the resulting integral takes the form: x-x3 -du S- S- S- S- U 1-u4 4u 4-u² 4u (24²) 2 -du 4- u -du -du
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