The graph of the function f(x) = 1 – x² is the upper half of the unit circle. On that curve (see the figure below) we have marked a point P(x, y). normal P(x, y) tangent (-1, 0) (1, 0) (a) What is the slope of the normal at P? Express your an- swer in terms of x and y. (b) Deduce from (a) the slope of the tangent at P. Express your answer in terms of x and y. (c) Confirm your answer in (b) by calculating V1 – (x + h)? – VI – x² | f'(x) = lim h→0 h HINT: First rationalize the numerator of the difference quo- tient by multiplying both numerator and denominator by V1– (x + h)? + VI– x². |

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
The graph of the function f(x) = 1 – x² is the upper half
of the unit circle. On that curve (see the figure below) we
have marked a point P(x, y).
normal
P(x, y)
tangent
(-1, 0)
(1, 0)
(a) What is the slope of the normal at P? Express your an-
swer in terms of x and y.
(b) Deduce from (a) the slope of the tangent at P. Express
your answer in terms of x and y.
(c) Confirm your answer in (b) by calculating
V1 – (x + h)? – VI – x²
|
f'(x) = lim
h→0
h
HINT: First rationalize the numerator of the difference quo-
tient by multiplying both numerator and denominator by
V1– (x + h)? + VI– x².
|
Transcribed Image Text:The graph of the function f(x) = 1 – x² is the upper half of the unit circle. On that curve (see the figure below) we have marked a point P(x, y). normal P(x, y) tangent (-1, 0) (1, 0) (a) What is the slope of the normal at P? Express your an- swer in terms of x and y. (b) Deduce from (a) the slope of the tangent at P. Express your answer in terms of x and y. (c) Confirm your answer in (b) by calculating V1 – (x + h)? – VI – x² | f'(x) = lim h→0 h HINT: First rationalize the numerator of the difference quo- tient by multiplying both numerator and denominator by V1– (x + h)? + VI– x². |
Expert Solution
Step 1

Introduction:-

Slope of line is ratio of differences in y and x

Slope of Normal and Tangent are Negative reciprocal of each other

Slope of tangent at point is derivative at that point

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