Calculus O 201 6 Kuta Softw are LLC. A11 Name rig hts reserved. ID: 1 Motion Review Date Period A particle moves along a horizontal line. Its position function is s(t) for t2 0. For each problem, find the velocity function t), the acceleration function a(t), the times t when the particle changes directions, the intervals of time when the particle is moving left and moving right, and the times t when the acceleration is 0. 1) s() = r – 91 2) s(1) = r– 281 + 1961

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Calculus
O 201 6 Kuta
Name
ID: 1
Softw ar e LLC.
A 11
rig hts rCserved.
Motion Review
Date
Period
A particle moves along a horizontal line. Its position function is s(t) for t2 0. For each
problem, find the velocity function vt), the acceleration function a(t), the times t when the
particle changes directions, the intervals of time when the particle is moving left and moving
right, and the times t when the acceleration is 0.
1) s() = r – 91
2) s(t) = r- 281 + 196t
A particle moves along a horizontal line. Its position function is s(r) for t2 0. For each
problem, find the position, velocity, speed, and acceleration at the given value for t.
4) s(1) = - 30/² + 225r: at 1 4
3) sl)=-- 561; at - 6
Transcribed Image Text:Calculus O 201 6 Kuta Name ID: 1 Softw ar e LLC. A 11 rig hts rCserved. Motion Review Date Period A particle moves along a horizontal line. Its position function is s(t) for t2 0. For each problem, find the velocity function vt), the acceleration function a(t), the times t when the particle changes directions, the intervals of time when the particle is moving left and moving right, and the times t when the acceleration is 0. 1) s() = r – 91 2) s(t) = r- 281 + 196t A particle moves along a horizontal line. Its position function is s(r) for t2 0. For each problem, find the position, velocity, speed, and acceleration at the given value for t. 4) s(1) = - 30/² + 225r: at 1 4 3) sl)=-- 561; at - 6
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Note : There are many subparts and questions in the given questions. So I will answer the first two subparts

            from the both questions. Please send other questions separately.

(1)

Given :

The positions functions is s(t) for t0 :

s(t)=t3-9t2

(a) The velocity function v(t) :

For the velocity function differentiate s(t) with respect to t :

v(t)=s'(t)=3t2-18t

Hence, the velocity function is v(t)=3t2-18t

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