calculus medium, please solve questionnnn 8
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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calculus medium, please solve questionnnn 8
![(-1)
(1) The series Σk=1 is:
k4/s
A) conditionally convergent B) absolutely convergent
(2) The sequence {(1 − 2)"},
A) converges to e7
(3)√3249 dx =
B) converges to e-7
A) B) 플
dx
√x²+2x+10
(4) The interval of convergence of the power series Ex=1
A) [0]
B) (-/-)
C) (-3, 3)
for f
B) x = 10 sin 0
(5) The appropriate substitution
A) x+1=3 tan 8
(6) S (x+2)²
dx =
A)+In/x+3/+c B)₂+In/x+2/+c
C) converges to -7
C) F
B) x = ln(2), ln(-3)
A) - 3
2
1* is:
C) divergent
D) (-∞0,00)
(7) A formula for the general term starting with n = 1 of:
A)
B) {} c) {(-1) 3"}
(8) The solutions of e²x + ex-6=0 are:
A) x = ln(2), In(3)
2k-1
(9) The sum Ek-1
3k
C) x 1 = 2 tan 0
39
4'16
D) {(-1)+131)
472
B) 12/12
27 81
64 256
C) x = 2,-3
D) Diverges
C)+c D) In x + 2 + c
x+2
D) D.N.E
D) diverges
C) 2
D) x-1= 3 tan 0
is:
D) x = ln (2)
312
D) 2/2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5231f5b4-e859-48c1-839f-bbb3459ab86b%2Fb48ddef6-2b8c-4f99-9fa2-f9f0ab165a03%2Fxdo4dnp_processed.png&w=3840&q=75)
Transcribed Image Text:(-1)
(1) The series Σk=1 is:
k4/s
A) conditionally convergent B) absolutely convergent
(2) The sequence {(1 − 2)"},
A) converges to e7
(3)√3249 dx =
B) converges to e-7
A) B) 플
dx
√x²+2x+10
(4) The interval of convergence of the power series Ex=1
A) [0]
B) (-/-)
C) (-3, 3)
for f
B) x = 10 sin 0
(5) The appropriate substitution
A) x+1=3 tan 8
(6) S (x+2)²
dx =
A)+In/x+3/+c B)₂+In/x+2/+c
C) converges to -7
C) F
B) x = ln(2), ln(-3)
A) - 3
2
1* is:
C) divergent
D) (-∞0,00)
(7) A formula for the general term starting with n = 1 of:
A)
B) {} c) {(-1) 3"}
(8) The solutions of e²x + ex-6=0 are:
A) x = ln(2), In(3)
2k-1
(9) The sum Ek-1
3k
C) x 1 = 2 tan 0
39
4'16
D) {(-1)+131)
472
B) 12/12
27 81
64 256
C) x = 2,-3
D) Diverges
C)+c D) In x + 2 + c
x+2
D) D.N.E
D) diverges
C) 2
D) x-1= 3 tan 0
is:
D) x = ln (2)
312
D) 2/2
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