Calculator Use can help on complicated functions: tep 1: Given are the two curves y = f(x) and y = g(x). equating both the curves to get the value of interval [a,b] where the given curves intersects. Step 2 : The area between the two curves bounded by the x axis is given by the formula A = J [f(x) - g(x)]dx over[a,b]; where f(x) is upper curve and g(x) is the lower curve. Blue area is the area below: f(x). yi = f(x)>> then 2nd calc integrate >> then x = a, then x = b. Red area is area below g(x). Same thing as above Area(enclosed) = area(f(x)) – area(g(x)) Note: You will need to solve equations for Y 5. ind the area (decimal): formed by the curves : x² + y² =1 and x72+ y ½= 1 in quadrant I.
Calculator Use can help on complicated functions: tep 1: Given are the two curves y = f(x) and y = g(x). equating both the curves to get the value of interval [a,b] where the given curves intersects. Step 2 : The area between the two curves bounded by the x axis is given by the formula A = J [f(x) - g(x)]dx over[a,b]; where f(x) is upper curve and g(x) is the lower curve. Blue area is the area below: f(x). yi = f(x)>> then 2nd calc integrate >> then x = a, then x = b. Red area is area below g(x). Same thing as above Area(enclosed) = area(f(x)) – area(g(x)) Note: You will need to solve equations for Y 5. ind the area (decimal): formed by the curves : x² + y² =1 and x72+ y ½= 1 in quadrant I.
Calculator Use can help on complicated functions: tep 1: Given are the two curves y = f(x) and y = g(x). equating both the curves to get the value of interval [a,b] where the given curves intersects. Step 2 : The area between the two curves bounded by the x axis is given by the formula A = J [f(x) - g(x)]dx over[a,b]; where f(x) is upper curve and g(x) is the lower curve. Blue area is the area below: f(x). yi = f(x)>> then 2nd calc integrate >> then x = a, then x = b. Red area is area below g(x). Same thing as above Area(enclosed) = area(f(x)) – area(g(x)) Note: You will need to solve equations for Y 5. ind the area (decimal): formed by the curves : x² + y² =1 and x72+ y ½= 1 in quadrant I.
for each of the following questions, first sketch the relevant area then write out the definite integral that will exact value
Transcribed Image Text:Calculator Use can help on complicated functions:
tep 1: Given are the two curves y = f(x) and y = g(x). equating both the curves to get the value of interval
[a,b] where the given curves intersects.
Step 2 : The area between the two curves bounded by the x axis is given by the formula
A = ] [f(x) - g(x)]dx over[a,b]; where f(x) is upper curve and g(x) is the lower curve.
Blue area is the area below: f(x).
y1 = f(x)>> then 2nd calc integrate >> then x =
a, then x = b.
Red area is area below g(x). Same thing as above
Area(enclosed) = area(f(x)) – area(g(x))
Note: You will need to solve equations for Y
2+ y 2= 1
5. sind the area (decimal): formed by the curves : x2 + y2 = 1
in quadrant I.
and X
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
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![Calculator Use can help on complicated functions:
tep 1: Given are the two curves y = f(x) and y = g(x). equating both the curves to get the value of interval
[a,b] where the given curves intersects.
Step 2 : The area between the two curves bounded by the x axis is given by the formula
A = ] [f(x) - g(x)]dx over[a,b]; where f(x) is upper curve and g(x) is the lower curve.
Blue area is the area below: f(x).
y1 = f(x)>> then 2nd calc integrate >> then x =
a, then x = b.
Red area is area below g(x). Same thing as above
Area(enclosed) = area(f(x)) – area(g(x))
Note: You will need to solve equations for Y
2+ y 2= 1
5. sind the area (decimal): formed by the curves : x2 + y2 = 1
in quadrant I.
and X](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fec70a3af-7012-41b5-84d0-077491201fef%2Ffa08e43a-fb75-4b5a-ab8a-7499d9abed65%2Fgyl8cbn_processed.png&w=3840&q=75)
