Calculating the pH at equivalence of a titration A chemist titrates 250.0 mL of a 0.5586M cyanic acid (HCNO) solution with 0.6468 M NaOH solution at 25 °C. Calculate the pH at equivalence. The pK, of cyanic acid is 3.46. Round your answer to 2 decimal places. the solution equals the initial volume plus the volume of NaOH solution added.

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**Calculating the pH at Equivalence of a Titration**

A chemist titrates 250.0 mL of a 0.5586 M cyanic acid (HCNO) solution with 0.6486 M NaOH solution at 25 °C. Calculate the pH at equivalence. The \( pK_a \) of cyanic acid is 3.46.

Round your answer to 2 decimal places.

*Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of NaOH solution added.*

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- pH = [ ]

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Transcribed Image Text:**Calculating the pH at Equivalence of a Titration** A chemist titrates 250.0 mL of a 0.5586 M cyanic acid (HCNO) solution with 0.6486 M NaOH solution at 25 °C. Calculate the pH at equivalence. The \( pK_a \) of cyanic acid is 3.46. Round your answer to 2 decimal places. *Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of NaOH solution added.* **[Input Box]** - pH = [ ] **Button options:** - Explanation - Check This is presented within an educational software environment, with interactive features for students to input and check their answers.
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