I guessed on this question. Can you please help how to solve it? Chapter 9 HomeworkCalculating [H30+] and [OH-] In SolutionsAcidicNeutralBasicOH]= 4x 1o 12 M[OH] = 4x 10 2 M(OH = 9× 10 ° M[OH ] = 1×10 7 M[OH 8x 104M(OH 2 x 10 10 M[OH | = 5x 10M(OH 4x 10 13 MPrevious AnswersAll attempts used; correct answer displayedA solution's acidity or basicity can be determined by knowing either the concentration of the hydronium ion or the hydroxide ion. If the hydroxide ion concentratiis less than its concentration in pure water (1 x 10 M), then the hydronium ion concentration must be greater than its concentration in pure water becauseP Pearson| Privacy Policy I Permissions Contact Us /Copyright 2020 Pearson Education Inc. All rights reserved. I Terms of Usehulu McGraw-Hill ConnectPart Time Job Opp... M Broward College H..VZ CollegeApp: US..wco ASC South Campus...OneloginMyLab & Mastenng. View Available Hint(s)ResetHelpP PearsonCopyright 2020 Pearson Education Inc. All rights reserved. I Terms of Use | Privacy Policyy I Permissions | Contact UsI11:46 PMrchW11/14/2020

Given hydroxide ion concentrations, [OH-] = 4 × 10-12 M[OH-] = 9 × 10-9 M[OH-] = 2 × 10-10 M[OH-] = 4 × 10-13 M[OH-] = 1 × 10-7 M[OH-] = 4 × 10-2 M[OH-] = 8 × 10-4 M[OH-] = 5 × 10-5 MGiven information, [H3O+] = Kw[OH-] = 1 × 10-14 M[OH-] Calculate the hydronium ion concentration, For, [OH-] = 4 × 10-12 M[H3O+] = 1 × 10-14 M4 × 10-12 M = 2.5 × 10-3 MFor, [OH-] = 9 × 10-9 M[H3O+] = 1 × 10-14 M9 × 10-9 M = 1.1 × 10-6 MFor, [OH-] = 2 × 10-10 M[H3O+] = 1 × 10-14 M2 × 10-10 M = 5 × 10-5 MFor, [OH-] = 4 × 10-13 M[H3O+] = 1 × 10-14 M4 × 10-13 M = 2.5 × 10-2 MFor, [OH-] = 1 × 10-7 M[H3O+] = 1 × 10-14 M1 × 10-7 M = 1 × 10-7 MFor, [OH-] = 4 × 10-2 M[H3O+] = 1 × 10-14 M4 × 10-2 M = 2.5 × 10-13 MFor, [OH-] = 8 × 10-4 M[H3O+] = 1 × 10-14 M8 × 10-4 M = 1.25 × 10-11 MFor, [OH-] = 5 × 10-5 M[H3O+] = 1 × 10-14 M 5 × 10-5 M = 2 × 10-10 M Classification,