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Calculate the x-component of the forces. R =175 cos 60° +130 cos 160° %3D R =-34.66 gm %3D Calculate the x-component of the forces. R, = 175 sin 60° +130 sin 160° %3D R, = 196.2 gm Calculate the magnitude of the resultant. R = (R,) +(R,) %3D (-34.66) +(196.2)* R= 199.24 g %3D Calculate the direction. R, -1 = tan R (196.2) -1 = tan (-34.66) = 80°

Calculate the x-component of the forces. R =175 cos 60° +130 cos 160° %3D R =-34.66 gm %3D Calculate the x-component of the forces. R, = 175 sin 60° +130 sin 160° %3D R, = 196.2 gm Calculate the magnitude of the resultant. R = (R,) +(R,) %3D (-34.66) +(196.2)* R= 199.24 g %3D Calculate the direction. R, -1 = tan R (196.2) -1 = tan (-34.66) = 80°

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Component Method for Problem 2:** **Calculate the X-Component of the Forces:** \[ R_x = 175 \cos 60^\circ + 130 \cos 160^\circ \] \[ R_x = -34.66 \, \text{gm} \] **Calculate the Y-Component of the Forces:** \[ R_y = 175 \sin 60^\circ + 130 \sin 160^\circ \] \[ R_y = 196.2 \, \text{gm} \] **Calculate the Magnitude of the Resultant:** \[ R = \sqrt{(R_x)^2 + (R_y)^2} \] \[ = \sqrt{(-34.66)^2 + (196.2)^2} \] \[ R = 199.24 \, \text{gm} \] **Calculate the Direction:** \[ \theta = \tan^{-1} \left[ \frac{R_y}{R_x} \right] \] \[ = \tan^{-1} \left[ \frac{196.2}{-34.66} \right] \] \[ \theta = 80^\circ \]
Transcribed Image Text:**Component Method for Problem 2:** **Calculate the X-Component of the Forces:** \[ R_x = 175 \cos 60^\circ + 130 \cos 160^\circ \] \[ R_x = -34.66 \, \text{gm} \] **Calculate the Y-Component of the Forces:** \[ R_y = 175 \sin 60^\circ + 130 \sin 160^\circ \] \[ R_y = 196.2 \, \text{gm} \] **Calculate the Magnitude of the Resultant:** \[ R = \sqrt{(R_x)^2 + (R_y)^2} \] \[ = \sqrt{(-34.66)^2 + (196.2)^2} \] \[ R = 199.24 \, \text{gm} \] **Calculate the Direction:** \[ \theta = \tan^{-1} \left[ \frac{R_y}{R_x} \right] \] \[ = \tan^{-1} \left[ \frac{196.2}{-34.66} \right] \] \[ \theta = 80^\circ \]
**Part 2: Component Method** *Do this only!* Using the component method, determine the magnitude and direction of the forces described in Part 2 and analytically determine the magnitude and direction of their resultant. Record your results in the table below. **Component Determination** | Vector | Magnitude | X-Component | Y-Component | |--------|-----------|-------------|-------------| | 1 | | | | | 2 | | \(R_x =\) | \(R_y =\) | Resultant \( R = \) __________ \( \Theta_R = \) __________
Transcribed Image Text:**Part 2: Component Method** *Do this only!* Using the component method, determine the magnitude and direction of the forces described in Part 2 and analytically determine the magnitude and direction of their resultant. Record your results in the table below. **Component Determination** | Vector | Magnitude | X-Component | Y-Component | |--------|-----------|-------------|-------------| | 1 | | | | | 2 | | \(R_x =\) | \(R_y =\) | Resultant \( R = \) __________ \( \Theta_R = \) __________
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