**Title: Calculating Work Done on an Inclined Plane****Problem Statement:**Calculate the work done (in Joules) by an 80.0 kg man who pushes a crate 3.95 meters up along a ramp that makes an angle of 20.0° with the horizontal. He exerts a force of 455 N on the crate parallel to the ramp and moves at a constant speed. Be certain to include the work he does on the crate and on his body to get up the ramp.**Diagram Explanation:**The diagram shows a man pushing a crate up a ramp. The ramp is inclined at an angle of 20.0° to the horizontal. The force exerted by the man, denoted by F, is 455 N and acts parallel to the surface of the ramp. **Solution:**The work done, denoted as W, is calculated with the following formula:\[ W = F \times d \]Where:- \( F = 455 \, \text{N} \) (force exerted),- \( d = 3.95 \, \text{m} \) (distance moved along the ramp).Substituting these values, we get:\[ W = 455 \, \text{N} \times 3.95 \, \text{m} = 1797.25 \, \text{J} \]Thus, the total work done by the man is \( 1797.25 \, \text{J} \).**Conclusion:**The total work calculated here takes into account the energy used not just in moving the crate, but also includes the effort of moving his own body up the incline, as the work exerted is parallel to the ramp and at a constant speed.

Given that - Mass of the man Angle Distance Force To Find - We have to determine the work done by…

Calculate the work done (in J) by an 80.0 kg man who pushes a crate 3.95 m up along a ramp that makes an angle of 20.0 with the horizontal. (See the figure below.) He exerts a force of 455 N on the crate parallel to the ramp and moves at a constant speed. Be certain to include the work he does on the crate and on his body to get up the ramp. 1797.20 x

Calculate the work done (in J) by an 80.0 kg man who pushes a crate 3.95 m up along a ramp that makes an angle of 20.0 with the horizontal. (See the figure below.) He exerts a force of 455 N on the crate parallel to the ramp and moves at a constant speed. Be certain to include the work he does on the crate and on his body to get up the ramp. 1797.20 x

College Physics

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

**Title: Calculating Work Done on an Inclined Plane**

**Problem Statement:**

Calculate the work done (in Joules) by an 80.0 kg man who pushes a crate 3.95 meters up along a ramp that makes an angle of 20.0° with the horizontal. He exerts a force of 455 N on the crate parallel to the ramp and moves at a constant speed. Be certain to include the work he does on the crate and on his body to get up the ramp.

**Diagram Explanation:**

The diagram shows a man pushing a crate up a ramp. The ramp is inclined at an angle of 20.0° to the horizontal. The force exerted by the man, denoted by F, is 455 N and acts parallel to the surface of the ramp.

**Solution:**

The work done, denoted as W, is calculated with the following formula:

\[ W = F \times d \]

Where:
- \( F = 455 \, \text{N} \) (force exerted),
- \( d = 3.95 \, \text{m} \) (distance moved along the ramp).

Substituting these values, we get:

\[ W = 455 \, \text{N} \times 3.95 \, \text{m} = 1797.25 \, \text{J} \]

Thus, the total work done by the man is \( 1797.25 \, \text{J} \).

**Conclusion:**

The total work calculated here takes into account the energy used not just in moving the crate, but also includes the effort of moving his own body up the incline, as the work exerted is parallel to the ramp and at a constant speed.

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