**Transcription for Educational Website:**"6. Calculate the wavelength of a photon with \(5.06 \times 10^{-19}\) J of energy."**Explanation:**This question involves calculating the wavelength (\(\lambda\)) of a photon using its energy (\(E\)). The relationship between a photon's energy and its wavelength can be determined using the equation:\[ E = \frac{hc}{\lambda} \]Where:- \(E\) is the energy of the photon in joules (J).- \(h\) is Planck's constant, approximately \(6.626 \times 10^{-34} \text{ J s}\).- \(c\) is the speed of light in a vacuum, approximately \(3.00 \times 10^8 \text{ m/s}\).- \(\lambda\) is the wavelength of the photon in meters (m).To find the wavelength, rearrange the equation to:\[ \lambda = \frac{hc}{E} \]By substituting the given values into this formula, you can calculate the wavelength of the photon.

The photon is an elementary particle that has the quantum of the electromagnetic field. This electromagnetic field includes electromagnetic radiation such as light and radio waves and the force carrier for the electromagnetic force. Photons do not have any mass, and they always travel at the speed of light in a vacuum. When the electron makes a transition from a higher energy level to lower energy, it emits a photon of quantized energy equals the difference in energies of the levels. To determine the photon's frequency and energy in the given problem, we will first determine the photon's wavelength by using the Rydberg equation.Given data: *The energy is E=5.06×10-19 J. The expression for the Energy of the wavelength is given as, E=hcλ Here, h is the Planck's constant and its value is 6.64×10-34 J·s and c is the speed of light and its value is 3×10-8 m/s. Substitute the values in the above equation, 5.06×10-19 J=6.64×10-34 J·s×3×108 m/sλλ=3.93×10-7 mThus, the wavelength is 3.93×10-7 m.

Answered: Calculate the wavelength of a photon…

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Advanced Physics

Calculate the wavelength of a photon with 5.06x10-1ºJ of energy.

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