Calculate the wavelength of a photon with 5.06x10-1ºJ of energy.
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![**Transcription for Educational Website:**
"6. Calculate the wavelength of a photon with \(5.06 \times 10^{-19}\) J of energy."
**Explanation:**
This question involves calculating the wavelength (\(\lambda\)) of a photon using its energy (\(E\)). The relationship between a photon's energy and its wavelength can be determined using the equation:
\[ E = \frac{hc}{\lambda} \]
Where:
- \(E\) is the energy of the photon in joules (J).
- \(h\) is Planck's constant, approximately \(6.626 \times 10^{-34} \text{ J s}\).
- \(c\) is the speed of light in a vacuum, approximately \(3.00 \times 10^8 \text{ m/s}\).
- \(\lambda\) is the wavelength of the photon in meters (m).
To find the wavelength, rearrange the equation to:
\[ \lambda = \frac{hc}{E} \]
By substituting the given values into this formula, you can calculate the wavelength of the photon.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2302c526-9755-4035-b569-0a02cd47add7%2F61ef0e3d-336a-4326-a143-cba1e76c8416%2Frohxawm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Transcription for Educational Website:**
"6. Calculate the wavelength of a photon with \(5.06 \times 10^{-19}\) J of energy."
**Explanation:**
This question involves calculating the wavelength (\(\lambda\)) of a photon using its energy (\(E\)). The relationship between a photon's energy and its wavelength can be determined using the equation:
\[ E = \frac{hc}{\lambda} \]
Where:
- \(E\) is the energy of the photon in joules (J).
- \(h\) is Planck's constant, approximately \(6.626 \times 10^{-34} \text{ J s}\).
- \(c\) is the speed of light in a vacuum, approximately \(3.00 \times 10^8 \text{ m/s}\).
- \(\lambda\) is the wavelength of the photon in meters (m).
To find the wavelength, rearrange the equation to:
\[ \lambda = \frac{hc}{E} \]
By substituting the given values into this formula, you can calculate the wavelength of the photon.
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