Calculate the volumes needed to create a 50 mL buffer solution with a target pH of 4.20. Use 0.10 M solutions from List E and List F. (Use HCOOH and HCOOK, and check if the work provided below is correct) HCOOH, HCOOK A CB ott = oka + log List E 0.10 M HCOOH K = 1.8 x 10-4 0.10 M CH₂COOH K₂ = 1.8 x 10-s nislg 0.10 M NH,OH K = 1.8 x 10-5 0.10 M CH,NH, K=4.4 x 10-4 [6] ↑ List F 0.10 M CH,NH,CI 0.10 M NHẠCI 0.10 M CH,COONa 0.10 M HCOOK 0.10 M HCOONa 0.10 M CH,COOK 4.20 3.74 CHOOOK] loẾU COOHJ logi
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Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.
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![Calculate the volumes needed to create a 50 mL buffer solution with a target pH of 4.20. Use
0.10 M solutions from List E and List F. (Use HCOOH and HCOOK, and check if the work
provided below is correct)
HCOOH, HCOOK
A
CB
он = рка+
List E
0.10 M HCOOH
K = 1.8 x 10-4
0.10 M CH₂COOH
K₁ = 1.8 x 10-5
0.10 M NH OH
K=1.8 x 10-5
0.10 M CHẠNH,
K = 4.4 x 10-4
↓
List F
0.10 M CH,NH,CI
0.10 M NHẠCI
0.10 M CH,COONa
0.10 M HCOOK
0.10 M HCOONa
0.10 M CH,COOK
4.20 3.74 +
2.88 = CHCOOK]
Снсоон]
50mL, .050L
X= vol HCOOK
050-XE VỚI HCCH
[B]
[A]
2.88=
2.56
[HOOOK]
log pнссон]
2x
(0.10M-X)/.05L
(0-10M (050-x)/05L 0.1-2x
2x
0.1-2x
2.88 0.1-2x) = 2x
x = 0.0371
0.050-x = 0.0129
371mL HCOOK
12.9m2 HcoH](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe4d1a1a7-946c-4b3e-81bf-38545fbbd49b%2Fd95867e6-59a6-442e-9f3b-eef4067b5086%2F30uxjjf_processed.jpeg&w=3840&q=75)
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