Calculate the volume (in mL) of 0.100 M CaCl2 needed to produce 1.00 g of . There is an excess of Na₂CO3. Na₂CO3(aq) +CaCl₂(aq) - → > 2 NaCl(aq) + CaCO3(s) Molar mass of calcium carbonate = 100.09 g/mol Volume of calcium chloride = mL CaCO3(s)
Calculate the volume (in mL) of 0.100 M CaCl2 needed to produce 1.00 g of . There is an excess of Na₂CO3. Na₂CO3(aq) +CaCl₂(aq) - → > 2 NaCl(aq) + CaCO3(s) Molar mass of calcium carbonate = 100.09 g/mol Volume of calcium chloride = mL CaCO3(s)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Chemical Reaction and Calculation**
**Reaction Equation:**
\[
\text{Na}_2\text{CO}_3(aq) + \text{CaCl}_2(aq) \rightarrow 2 \text{NaCl}(aq) + \text{CaCO}_3(s)
\]
**Objective:**
Calculate the volume (in mL) of 0.100 M \(\text{CaCl}_2\) needed to produce 1.00 g of \(\text{CaCO}_3(s)\).
**Given Information:**
- **Molar Mass of Calcium Carbonate (\(\text{CaCO}_3\))**: 100.09 g/mol
- **There is an excess of \(\text{Na}_2\text{CO}_3\).**
**Calculation:**
To find the required volume of calcium chloride solution, calculate the moles of \(\text{CaCO}_3\) produced, then use stoichiometry and molarity concepts to find the volume needed.
- **Formula for Moles Calculation**:
\[
\text{moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}}
\]
- Calculate moles of \(\text{CaCO}_3\):
\[
\text{moles of CaCO}_3 = \frac{1.00 \, \text{g}}{100.09 \, \text{g/mol}}
\]
- Use the balanced chemical equation to determine moles of \(\text{CaCl}_2\) needed:
- 1 mole of \(\text{CaCl}_2\) produces 1 mole of \(\text{CaCO}_3\).
- Use the molarity equation to calculate the volume:
\[
\text{Volume (L)} = \frac{\text{moles of }\text{CaCl}_2}{\text{Molarity (M)}}
\]
Convert volume from liters to milliliters.
**Volume of calcium chloride = [Answer in mL]**
**Diagram Explanation:**
There are no diagrams or graphs in the text.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F91687e8e-0450-4619-842e-d38d6872920e%2F1742f57e-b5c3-4c33-9629-0c25183a0a74%2F057x3c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Chemical Reaction and Calculation**
**Reaction Equation:**
\[
\text{Na}_2\text{CO}_3(aq) + \text{CaCl}_2(aq) \rightarrow 2 \text{NaCl}(aq) + \text{CaCO}_3(s)
\]
**Objective:**
Calculate the volume (in mL) of 0.100 M \(\text{CaCl}_2\) needed to produce 1.00 g of \(\text{CaCO}_3(s)\).
**Given Information:**
- **Molar Mass of Calcium Carbonate (\(\text{CaCO}_3\))**: 100.09 g/mol
- **There is an excess of \(\text{Na}_2\text{CO}_3\).**
**Calculation:**
To find the required volume of calcium chloride solution, calculate the moles of \(\text{CaCO}_3\) produced, then use stoichiometry and molarity concepts to find the volume needed.
- **Formula for Moles Calculation**:
\[
\text{moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}}
\]
- Calculate moles of \(\text{CaCO}_3\):
\[
\text{moles of CaCO}_3 = \frac{1.00 \, \text{g}}{100.09 \, \text{g/mol}}
\]
- Use the balanced chemical equation to determine moles of \(\text{CaCl}_2\) needed:
- 1 mole of \(\text{CaCl}_2\) produces 1 mole of \(\text{CaCO}_3\).
- Use the molarity equation to calculate the volume:
\[
\text{Volume (L)} = \frac{\text{moles of }\text{CaCl}_2}{\text{Molarity (M)}}
\]
Convert volume from liters to milliliters.
**Volume of calcium chloride = [Answer in mL]**
**Diagram Explanation:**
There are no diagrams or graphs in the text.
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