Calculate the volume in liters of a 0.00735 mol/L calcium sulfate solution that contains 150. g of calcium sulfate (CaSO4). Round your answer to 3 significant digits. OL X 5
Calculate the volume in liters of a 0.00735 mol/L calcium sulfate solution that contains 150. g of calcium sulfate (CaSO4). Round your answer to 3 significant digits. OL X 5
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Educational Content: Calculating Solution Volume**
**Problem Statement:**
Calculate the volume in liters of a 0.00735 mol/L calcium sulfate solution that contains 15.0 g of calcium sulfate (CaSO₄). Round your answer to 3 significant digits.
**Solution Explanation:**
To solve this problem, follow these steps:
1. **Determine the molar mass of CaSO₄:**
- Calcium (Ca): 40.08 g/mol
- Sulfur (S): 32.07 g/mol
- Oxygen (O), 4 atoms: 4 × 16.00 g/mol = 64.00 g/mol
- Total molar mass = 40.08 + 32.07 + 64.00 = 136.15 g/mol
2. **Convert grams of CaSO₄ to moles:**
\[
\text{Moles of CaSO₄} = \frac{15.0 \, \text{g}}{136.15 \, \text{g/mol}}
\]
3. **Use molarity to find the volume:**
- Molarity (M) = moles of solute / liters of solution
- Rearrange to find volume (L):
\[
\text{Volume (L)} = \frac{\text{Moles of CaSO₄}}{0.00735 \, \text{mol/L}}
\]
4. **Compute the answer and round to 3 significant figures.**
**Box for User Input:**
[ ] L
**Options:**
- [ ] Check
- [ ] Save For Later
- [ ] Submit Assignment
**Note:**
Ensure that all calculations are precise and that final answers are rounded appropriately to maintain accuracy in reporting.
**Additional Resources:**
- Chemistry textbooks for reference on molarity and solution calculations.
- Online chemistry simulators for practice problems.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9ce1fa32-745b-446a-832b-1aa8581f8e40%2F25f3ee1d-13e0-4c42-aa30-0a31d0e4b94e%2Fz1v2hdi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Educational Content: Calculating Solution Volume**
**Problem Statement:**
Calculate the volume in liters of a 0.00735 mol/L calcium sulfate solution that contains 15.0 g of calcium sulfate (CaSO₄). Round your answer to 3 significant digits.
**Solution Explanation:**
To solve this problem, follow these steps:
1. **Determine the molar mass of CaSO₄:**
- Calcium (Ca): 40.08 g/mol
- Sulfur (S): 32.07 g/mol
- Oxygen (O), 4 atoms: 4 × 16.00 g/mol = 64.00 g/mol
- Total molar mass = 40.08 + 32.07 + 64.00 = 136.15 g/mol
2. **Convert grams of CaSO₄ to moles:**
\[
\text{Moles of CaSO₄} = \frac{15.0 \, \text{g}}{136.15 \, \text{g/mol}}
\]
3. **Use molarity to find the volume:**
- Molarity (M) = moles of solute / liters of solution
- Rearrange to find volume (L):
\[
\text{Volume (L)} = \frac{\text{Moles of CaSO₄}}{0.00735 \, \text{mol/L}}
\]
4. **Compute the answer and round to 3 significant figures.**
**Box for User Input:**
[ ] L
**Options:**
- [ ] Check
- [ ] Save For Later
- [ ] Submit Assignment
**Note:**
Ensure that all calculations are precise and that final answers are rounded appropriately to maintain accuracy in reporting.
**Additional Resources:**
- Chemistry textbooks for reference on molarity and solution calculations.
- Online chemistry simulators for practice problems.
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