Calculate the transmittance percentage (%T) of a sample that has a absorbance of 0.289 at 535nm. 75.2% 28.9% O 51.3% 123.1% 48.7%
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- Question 2T-Mobile Wi-Fi ? • 27% O 1 9:41 PM Done 3 of 4 O TL O a FOU FIJ FIJ 3 FJ 6 FOU GGG Nas i student.desmos. corvactivitybuilcer/student/608aboce08264docndJees97screentds0a3d0613-1d04-496a-989c-54rad466a7a Update Apos a CnCcurse Care. Clara Destiny sho 6 Imoloymunt Center * Login Sesicn Exaration. b Buling Aasociste. Skar i Vew Fartrait Droo. O Nursing: Tradion = Unit 4, Lesson 14: Using Normal Distributions for Exper. Dastiny Olengtu 5 of 14 Next > Researchers want to know the offect of captively raising birds on the weight cf the birds. The researchers begin with 100 birds dividad into 2 groups of 50 each. One group of 50 will be raised in captivity and the other 50 are tagged and released into the wid. After 5 yoars, all 100 birds pre collected and weighed. There are more than 10" different ways to regroup the 100 birds into groups of 50 again, so looking at all the combinations would be too time consuming to reproduce. In this case, we can run simulations to determine how the original…Let X have beta distribution with a =2 and B = 3. Then the mean and the variance of X, respectively, are Select one: O a. 0.04 and 04 O b. 0.02 and 0.04 O c. 0.4 and 0.04 O d. 0.4 and 0.20 The weekly downtime Y (in hours) for a certain industrial machine has approximately gamma distribution a =3 and B =2. The loss, in dollars, to the industrial operation as a result of this downtime is given by L = 30Y+2Y?. Find the expected value of L. Select one: O a. 180 O b. 98 Oc. 36 O d. 276 The length X to complete a certain key task in house construction is exponentially distributed with mean of 5 hours. The cost of completing this task is C = 10+20x2, Find the expected cost. Select one: O a. 1000 O b. 1010 O c. 510 O d. 500 sum of the dead load plus the The total sustained load on the concrete footing of a planned building is occupancy load. Suppose that the dead load X, has a gamma distribution with a = 10 and B= 30, whereas the occupancy load, X2 also has exponential distribution with e =…
- 6 X 01:13:24 eBook Quality Progress, February 2005, reports on improvements in customer satisfaction and loyalty made by Bank of America. A key measure of customer satisfaction is the response (on a scale from 1 to 10) to the question: "Considering all the business you do with Bank of America, what is your overall satisfaction with Bank of America?" Here, a response of 9 or 10 represents "customer delight." Suppose that the survey selected 480 customers. Assume that 45% of Bank of America customers would currently express customer delight. That is, assume p = .45. (a) Find the probability that the sample proportion obtained from the sample of 480 Bank of America customers would be within three percentage points of the population proportion. That is, find P(.42 ≤ § ≤ .48). (Round your answer to 4 decimal places. Do not round intermediate values. Round z-value to 2 decimal places.) P(.42 ≤ ≤.48)T-Mobile Wi-Fi ? 1 9:38 AM • 47% Done 9 of 14 931 A IX H FOL O a F T e st.dent.desmes.com/sctivitybulderistudent80ta0000a2e4a0cba771034screeride-5 w IG| + ! Apps 6 Cuteuran Cen Claa Domy she.. O Emolyment Cente Lagn Sanin ispiratin Update + Legn Sanion ipratken. Seling Asacriste signi P k Fort Pres = Mid-Unit IV Assessment Siynin O sng adticn. O Suu Dastiny Cteagu 5o1 Nex > Question 4 A representativo sample of oak trees in a forest shows the trees to have a moan circumference of 19,7 inches and a standard deviation of 1.3 inchca Assuming the çircumferences are normally distributed, estimate the proportion of oak trees in this forest that have a circumference greator then 21 inches. Submit 23 * + 4 6 8. delete E R Y U 1 S D F G H J L re V B M ol option command command option !! ... .. ..T-Mobile Wi-Fi ? 1 9:55 AM • 36% Done 14 of 18 FOL FIL FLL M F O Update i studeri.desmas.comiactivitybuilider/student/8088bcoe08264d0cod3ee897#screentc-beabee6: a5ct-4575-a535-f32a107ab362 E Sian in P View Portrait Pro. O Nursing: Tracition. 6 Legin Sessien Exolration. b Seling Assotiwe. Car tetiny tho.. O Emeloymert Cemter Aups a ntourse Carncc. く 10 of 14 Next > Unit 4. Lesson 14: Using Normal Distributions for Exper. Destry Orceu Rescarchers are tagging sharks using two different types of devices and want to know if the devices affect the heart rate of tho sharks. They tag one aroup of 8 sharks with a small device that collects a small amount of data and thoy tag another group of 8 sharks with a larger device that collects a large amount of data. They then measure the mean heart rate of the different groups and find that the difference in means is 2.5 beats per minute. Rescarchers run 1,000 simulations regrouping the data into 2 groups at random and record the differences in means…
- The table shows population statistics for the ages of Best Actor and Best Supporting Actor winners at an awards ceremony. The distributions of the ages are approximately bell-shaped. Compare the z-scores for the actors in the following situation. Best Actor Best Supporting Actor H=42.0 μ= 53.0 a=8.5 σ= 12 In a particular year, the Best Actor was 21 years old and the Best Supporting Actor was 56 years old. Determine the z-scores for each. Best Actor: z = Best Supporting Actor: z = (Round to two decimal places as needed.) Interpret the z-scores. unusual. The Best Actor was the mean, which the mean, which unusual. The Best Supporting Actor was Time Remaining: 01:05:53 NPork is the most preferred meat by a lot of meat consumers. Studies have shown that diets high in pork protein have favorable effects on a person's body composition. However, it is unclear whether these effects are specific to pork or whether consumption of other high protein meat diets have the same benefit. To investigate this, the nutritionist of a private diet center chose a random sample of overweight clients to participate in a 3-month program where each person is required to follow a restricted high-protein diet program with only one type of meat (chicken, fish, or pork). Before and after the program, the triglyceride level and weight of each client were recorded. Suppose the nutritionist asks your statistical advice for this study. 1. The nutritionist wants to study whether the mean change in triglyceride level of the clients differs among the three meat diets. She then asked your statistical advice considering that you have enough knowledge that using a parametric test…ll T-Mobile LTE 11:30 PM 85% Done 3 of 10 RXM M FOU Oe FI O as O TO F O F GGa an a sludert.desmos.com/activitybuilder/student/G07od3afe7ce2849451468b54soreenldx-3 E Apos a CnCcurs Cener. a CnCcursa Clara Destiny she.. O Emeloyment Conte Login Sersion Eepiration. Update : b Seling AsscER E Synin P view Portrait Prce. view Portait Preo. 6 N.rsng Tradlion. = Unit 4, Lesson Destiry Ofrenbu 8: Not Always Ideal 3 of 15 Next > What is Reasonable? What is the probability that you will flip heads when flipping a coin? Estimate the number of heads you will get when you flp a coin 20 times. Share with Class Share with Class %23 2 3 4 7 9 delete Q R T. Y U tab A F G H. J K. aps lock return X C B N M control option command command option !!
- T-Mobile Wi-Fi ? O 10:01 AM • 63% Done 3 of 5 Oe 90 FOU O a a e FDJ FOU FD.e 0 T M FOU O FOU w w w FDU FOU GNG A student.desmos.com/activitybuilder/student/607cd3afe7ce2849451466b5#screenldx=13 nCourse Connec. Clara Destiny sho... O Employment Center | 6 Login Sesslon Expiration. b Seling Associate-. Sign in P view Portrait Pro.. 6 Nursing: Tracition. , Lesson 8: Not Always Ideal oegbu 13 of 15 The weight of each cookie in a batch of a certain type of commercially produced cookie follows an approximately normal distribution with a mean of 11.32 grams and a When Elena throws a shot put during track and field practice, it travels an average of 26 feet with a standard deviation of 3 feet, and the distribution of lengths is approximately nomal. Approximately what percentage of her shots will travel less than 23 feet? standard deviation of 0.03 grams. Approximately what percent of the cookies weigh between 11.32 and 11.35 grams? Share with Class Submit ra & $4 %23 3 R. T Q W K H. D A B N C…ab ← → Homework 2: Initial Submission X CANVAS C Esc EBook Interactive Ps..... 153°F Clear canvas.eee.uci.edu/courses/61808/files/folder/homework?preview-25083953 A ! 1 O 2) 100 UCI students were randomly sampled (N = 100) and asked to rate their enjoyment of statistics on a scale of 0 to 10 where 0 represents an absence of enjoyment. Files The average enjoyment of statistics for this sample of 100 UCI students is 8. The average enjoyment of statistics among college students in general is 5 with a standard deviation of 1.5. FI AntAlmanac The distribution of college students' enjoyment of statistics is normal. The university wants to know whether the population of UCI students enjoys statistics more than the population of college students in general. 2 W You are asked to answer this question by conducting a "one sample z-test" and working through the five steps of null hypothesis significance testing, labeling each step and showing all work. In Step 5, present the inferential statistics…T-Mobile Wi-Fi ? I 12:12 AM •n 80% Done 11 of 12 RIE UX FIJ student.desmos.com/activitybulder/student/6062459508264d0cbd358totvscrearid-1oeb233b-4eb 401-aaa7-bE4679217 N a. . HI Apps a OnCourse Coene Clara Destiy shn 9 Empleyment Eenter Legir Sesen Espiration. 出 ☆ Logir Update! Seling Asedat = Unit 4. Lesson 11: Reducing Margin of Error Destiny Otcegbu Sien n P view Pnrtrai Prn S Nurang Tradition 3 of 10 Next > Finding a Job Elena and Clare are each working on a project about how high school students are having trouble finding jobs. Tney each find the proportion of students without jobs from a random sample, thern use a computer to do 1,000 simulations using the proportion they found and report the rasults. Elena says, "The proportion of high school students without jobs is about O.70 with a margin of error of 0.280. Clare says, "The proportion of high school students without jobs is about 0.74 with a margin of error of 0.138." Both students reported the margin of error based on 2…
