PART ACalculate the structural stiffness matrix of the truss shown. Take A = 300 mm² and E = 200 GPa.3 m3 m4 mGlobal coordinate system, global freedoms, and location vectors are shown in the figure below.Y++48754323A4O63525 KN1225 KN4211X

To assemble and formulate global stiffness matrix for the given truss

Answered: Calculate the structural stiffness…

Engineering

Civil Engineering

Calculate the structural stiffness matrix of the truss shown. Take A = 300 mm² and E = 200 GPa.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Please explain all question and draw diagram

A: Part 1. Calculate the displacements at the jointsGiven InformationThe truss structure is square with…

Q: Pin G B (b) (a)

Q: Given data: Stress=20 N/mm2 Area=5 mm2 Find the force applied on cross sectional area

A: Introduction : The given question is related with solid mechanics . In this question we are provided…

Q: Consider the pin-jointed truss as shown in figure below: A B D 30° 45° 90° 60° Coordinate direction…

Q: The strain components Ex, Ey, and Vxy are given for a point in a body subjected to plane strain.…

Q: a) How many unknown displacements are in the displacement vector? b) How many the displacement…

A: From the given Structure :

Q: A load P will be supported by a structure consisting of a rigid bar ABCD, a polymer [E = 2,300 ksi;…

Q: In the truss system shown in the figure below, there are totally nine bars. Pick any six of them and…

A: The six members chosen to calculate the forces are AB, AC, AD, BD, CD, DF. The reactions at hinged…

Question

PART A
Calculate the structural stiffness matrix of the truss shown. Take A = 300 mm² and E = 200 GPa.
3 m
3 m
4 m
Global coordinate system, global freedoms, and location vectors are shown in the figure below.
Y
++
4
8
7
5
4
3
2
3
A4
O
6
3
5
25 KN
1
2
25 KN
42
1
1
X

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Introduce the problem statement

VIEW

Step 2: Formulate member stiffness matrix for member-1

VIEW

Step 3: Formulate member stiffness matrix for member-2

VIEW

Step 4: Formulate member stiffness matrix for member-3

VIEW

Step 5: Formulate member stiffness matrix for member-4

VIEW

Step 6: Formulate member stiffness matrix for member-5

VIEW

Step 7: Assemble global stiffness matrix

VIEW

Solution

VIEW

Step by step

Solved in 8 steps with 16 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

3m +r = 3j + n is an equation to determine the stabily & determinacy for? 2D truss Frame Structure
D 4 m 2 m 1.5 m 2.5 m 2 m 1m 0.5 m B The assembly above consists of straight members forming a pyramid structure, as shown. The unit vectors for members AC and AD are as follows: UAc = {0.707i - 0.707j} • UAD = {0.530i + 0.848k} %3D Which of the following is closest to the angle between members AC and AD? a) 74.3° b) 1.19° c) 68.0° d) 90.4°
For the truss shown below, use symmetry to determine the displacement of the nodes and the stresses in each element. E=30E6 psi, Elements 1, 2, 4 and 5 have Area=10 in? and element 3 has Area = 20 in?, Use both software and hand calculations. 3 6 ft 2 -8 ft 8 ft 20,000 lb
Rigid bar ABC is supported by two aluminum alloy (E = 10,000 ksi) rods as shown below. The horizontal distance between rods (1) and (2) is a = 120 in. Rod (1) has a length of L1 = 87 in. and a cross-sectional area of A1 = 0.65 in.2. Rod (2) has a length of L2 = 84 in. and a cross-sectional area of A2 = 1.15 in.2. Rigid bar ABC is to remain horizontal under a load of P = 25 kips. Determine the distance x (in inches rounded to the nearest tenths) from joint A to the location of load P so that bar ABC remains horizontal.
2.4 The truss shown is the same as in Example 2.1 except that the area of bar ab is a variable. E = 200,000 MPa. (a) For what value of Aah is v. = 0? Is this a function of the magnitude of the applied load? (b) Is it possible to obtain zero u, by varying A? (c) Suppose the applied load were vertical rather than horizontal, would it then be possible to obtain zero u, by varying Aab? If so, for what value of Aab? What would be the corresponding v.? 500 kN Fah = +400.6 kN Aab 4 m 6 m 3 m Problem 2.4 Fac = -277.8 kN Aae = 8000 mm?
For the truss shown , The strength of the truss is assumed to be governed by the strength of member BC. Use Fy = 248 MPa and E = 200 GPa. The member BC is composed of two angular sections placed back-to-back separated by s = 8 mm as shown. If a = 4 meters,Properties of 75 x 75 x 12 mm angleA = 1774 mm²Ix = 0.92 x 10^6 mm^4Iy = 0.92 x 10^6 mm^4x = y = 23.25 mm 1. Using LRFD, which of the ff. most nearly gives the value of P in kiloNewtons. 2.Using LRFD, which of the ff. most nearly gives the reaction at D kiloNewtons. 3. Using ASD, which of the ff. most nearly gives the design strength of member BC in kiloNewtons.
Solve the problems neatly and show your complete solution with FBD. Write all numerical answers with the correct simplified units and rounded off to the nearest 3rd decimal.
Practice questions Solve clearly on a paper showing steps clearly including all diagrams Consider the truss shown below: a) Develop the global structural stiffness matrix [K] considering that the axial stiffness of both truss members is identical, i.e. (AE/L)1 = (AE/L)2= 100 kip/in. b) Report the matrix equation you would use to solve for the displacements at the unconstrained degrees of freedom. c) Report the matrix equation you would use to solve for the unknown reactions. Note that all members are axial members and deflections are small. You do not need to solve the matrix equations for displacements or reactions. LX 3 1 2 2 5 100 kip 50 kip LED Tt ! © B > Ր ...
a=83.7
Calculate the vertical translation of joint 5 for the truss structure shown in Fig. 3. We are given that the horizontal and vertical members have EA = 400,000 kip, and the rest of the members have EA = 100,000 kip. 24 ft 24 ft 24 ft 08 4 6 12 ft 1 10 kip 10 kip |10 kip 77 12 ft 24 ft 24 ft 12 ft Figure 3
Please Solve only showing answers and steps, not explanations
8. A rigid bar AB is supported by three rods. A load P = 350 kN is applied to the bar. The %3D modulus of elasticity of copper is 110 x 10^6 kN/m^2 and modulus of elasticity of steel is 200 x 10^6 kN/m^2. Steel rod A = 900 sq. mm Steel rod A = 900 sq. mm 2 m |Copper A = 1200 sq. mm 2 m A B 1 m - 1 m Determine the deformation in the rods (in mm). * Your answer Вack Next Clear form Never submit passwords through Google Forms. This form was created inside of Saint Louis University, Inc..