Calculate the standard error. May normality be assumed? (Round your answers to 4 decimal places.) Standard Error Normality (Click to select) (Click to select) (Click to select) v (Click to select) ♥ (a) 23, T =.27 (b) n- 47, 7 = .19 (c) (d) n 105, A = .20 n 459, A = .003
Calculate the standard error. May normality be assumed? (Round your answers to 4 decimal places.) Standard Error Normality (Click to select) (Click to select) (Click to select) v (Click to select) ♥ (a) 23, T =.27 (b) n- 47, 7 = .19 (c) (d) n 105, A = .20 n 459, A = .003
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![### Standard Error Calculation and Normality Assessment
In this exercise, you will calculate the standard error for different sample sizes and proportions, then determine if normality may be assumed. Please round your answers to 4 decimal places.
#### Data Table:
1. **(a)**
- Sample size (\(n\)): 23
- Proportion (\(\pi\)): 0.27
- **Standard Error**: [Input field]
- **Normality**: [Dropdown menu]
2. **(b)**
- Sample size (\(n\)): 47
- Proportion (\(\pi\)): 0.19
- **Standard Error**: [Input field]
- **Normality**: [Dropdown menu]
3. **(c)**
- Sample size (\(n\)): 105
- Proportion (\(\pi\)): 0.20
- **Standard Error**: [Input field]
- **Normality**: [Dropdown menu]
4. **(d)**
- Sample size (\(n\)): 459
- Proportion (\(\pi\)): 0.003
- **Standard Error**: [Input field]
- **Normality**: [Dropdown menu]
The exercise involves assessing whether the sample sizes and calculated standard errors allow us to assume that the distribution is approximately normal. The determination of normality is often based on rules such as the Central Limit Theorem, which can be applied under certain conditions related to sample size and proportion.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F251fd88f-21b3-4240-9699-9c3bf44b1b16%2F12ac9f27-ffd0-424d-ab09-9532e4443f38%2Fr7z53xxa_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Standard Error Calculation and Normality Assessment
In this exercise, you will calculate the standard error for different sample sizes and proportions, then determine if normality may be assumed. Please round your answers to 4 decimal places.
#### Data Table:
1. **(a)**
- Sample size (\(n\)): 23
- Proportion (\(\pi\)): 0.27
- **Standard Error**: [Input field]
- **Normality**: [Dropdown menu]
2. **(b)**
- Sample size (\(n\)): 47
- Proportion (\(\pi\)): 0.19
- **Standard Error**: [Input field]
- **Normality**: [Dropdown menu]
3. **(c)**
- Sample size (\(n\)): 105
- Proportion (\(\pi\)): 0.20
- **Standard Error**: [Input field]
- **Normality**: [Dropdown menu]
4. **(d)**
- Sample size (\(n\)): 459
- Proportion (\(\pi\)): 0.003
- **Standard Error**: [Input field]
- **Normality**: [Dropdown menu]
The exercise involves assessing whether the sample sizes and calculated standard errors allow us to assume that the distribution is approximately normal. The determination of normality is often based on rules such as the Central Limit Theorem, which can be applied under certain conditions related to sample size and proportion.
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