Calculate the standard enthalpy change for the reaction 2A +B= 2C+2D where the heats of formation are given in the following table: ΔΗ |(kJ/mol) Substance A -239 В -383 C 185 D -507 Express your answer in kilojoules.
Calculate the standard enthalpy change for the reaction 2A +B= 2C+2D where the heats of formation are given in the following table: ΔΗ |(kJ/mol) Substance A -239 В -383 C 185 D -507 Express your answer in kilojoules.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![**Calculate the Standard Enthalpy Change for the Reaction**
**Reaction:**
\[ 2A + B \rightarrow 2C + 2D \]
The heats of formation are given in the following table:
| Substance | \( \Delta H^\circ_f \) (kJ/mol) |
|-----------|-----------------------------|
| A | -239 |
| B | -383 |
| C | 185 |
| D | -507 |
**Instruction:**
Express your answer in kilojoules.
**Explanation:**
To find the standard enthalpy change (\( \Delta H^\circ_{\text{reaction}} \)) for the reaction, use the formula:
\[ \Delta H^\circ_{\text{reaction}} = \sum \Delta H^\circ_f (\text{products}) - \sum \Delta H^\circ_f (\text{reactants}) \]
**Detailed Steps:**
1. Calculate the total \( \Delta H^\circ_f \) for the products:
- \( 2 \times \Delta H^\circ_f (C) + 2 \times \Delta H^\circ_f (D) \)
- \( 2 \times 185 + 2 \times (-507) \)
2. Calculate the total \( \Delta H^\circ_f \) for the reactants:
- \( 2 \times \Delta H^\circ_f (A) + 1 \times \Delta H^\circ_f (B) \)
- \( 2 \times (-239) + (-383) \)
3. Plug these values into the formula and solve for \( \Delta H^\circ_{\text{reaction}} \).
This method will yield the standard enthalpy change in kilojoules.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fca50db5a-d826-4add-85c3-d6689308e727%2Fc5d56cdc-92e8-4c30-9821-b71d7ca513e3%2Flmxwlj_processed.png&w=3840&q=75)
Transcribed Image Text:**Calculate the Standard Enthalpy Change for the Reaction**
**Reaction:**
\[ 2A + B \rightarrow 2C + 2D \]
The heats of formation are given in the following table:
| Substance | \( \Delta H^\circ_f \) (kJ/mol) |
|-----------|-----------------------------|
| A | -239 |
| B | -383 |
| C | 185 |
| D | -507 |
**Instruction:**
Express your answer in kilojoules.
**Explanation:**
To find the standard enthalpy change (\( \Delta H^\circ_{\text{reaction}} \)) for the reaction, use the formula:
\[ \Delta H^\circ_{\text{reaction}} = \sum \Delta H^\circ_f (\text{products}) - \sum \Delta H^\circ_f (\text{reactants}) \]
**Detailed Steps:**
1. Calculate the total \( \Delta H^\circ_f \) for the products:
- \( 2 \times \Delta H^\circ_f (C) + 2 \times \Delta H^\circ_f (D) \)
- \( 2 \times 185 + 2 \times (-507) \)
2. Calculate the total \( \Delta H^\circ_f \) for the reactants:
- \( 2 \times \Delta H^\circ_f (A) + 1 \times \Delta H^\circ_f (B) \)
- \( 2 \times (-239) + (-383) \)
3. Plug these values into the formula and solve for \( \Delta H^\circ_{\text{reaction}} \).
This method will yield the standard enthalpy change in kilojoules.
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