Calculate the standard enthalpy change for the reaction 2A +B= 2C+2D where the heats of formation are given in the following table: ΔΗ |(kJ/mol) Substance A -239 В -383 C 185 D -507 Express your answer in kilojoules.

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**Calculate the Standard Enthalpy Change for the Reaction**

**Reaction:**

\[ 2A + B \rightarrow 2C + 2D \]

The heats of formation are given in the following table:

| Substance | \( \Delta H^\circ_f \) (kJ/mol) |
|-----------|-----------------------------|
| A         | -239                        |
| B         | -383                        |
| C         | 185                         |
| D         | -507                        |

**Instruction:**

Express your answer in kilojoules.

**Explanation:**

To find the standard enthalpy change (\( \Delta H^\circ_{\text{reaction}} \)) for the reaction, use the formula:

\[ \Delta H^\circ_{\text{reaction}} = \sum \Delta H^\circ_f (\text{products}) - \sum \Delta H^\circ_f (\text{reactants}) \]

**Detailed Steps:**

1. Calculate the total \( \Delta H^\circ_f \) for the products:
   - \( 2 \times \Delta H^\circ_f (C) + 2 \times \Delta H^\circ_f (D) \)
   - \( 2 \times 185 + 2 \times (-507) \)

2. Calculate the total \( \Delta H^\circ_f \) for the reactants:
   - \( 2 \times \Delta H^\circ_f (A) + 1 \times \Delta H^\circ_f (B) \)
   - \( 2 \times (-239) + (-383) \)

3. Plug these values into the formula and solve for \( \Delta H^\circ_{\text{reaction}} \).

This method will yield the standard enthalpy change in kilojoules.
Transcribed Image Text:**Calculate the Standard Enthalpy Change for the Reaction** **Reaction:** \[ 2A + B \rightarrow 2C + 2D \] The heats of formation are given in the following table: | Substance | \( \Delta H^\circ_f \) (kJ/mol) | |-----------|-----------------------------| | A | -239 | | B | -383 | | C | 185 | | D | -507 | **Instruction:** Express your answer in kilojoules. **Explanation:** To find the standard enthalpy change (\( \Delta H^\circ_{\text{reaction}} \)) for the reaction, use the formula: \[ \Delta H^\circ_{\text{reaction}} = \sum \Delta H^\circ_f (\text{products}) - \sum \Delta H^\circ_f (\text{reactants}) \] **Detailed Steps:** 1. Calculate the total \( \Delta H^\circ_f \) for the products: - \( 2 \times \Delta H^\circ_f (C) + 2 \times \Delta H^\circ_f (D) \) - \( 2 \times 185 + 2 \times (-507) \) 2. Calculate the total \( \Delta H^\circ_f \) for the reactants: - \( 2 \times \Delta H^\circ_f (A) + 1 \times \Delta H^\circ_f (B) \) - \( 2 \times (-239) + (-383) \) 3. Plug these values into the formula and solve for \( \Delta H^\circ_{\text{reaction}} \). This method will yield the standard enthalpy change in kilojoules.
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