Calculate the standard cell potential for the following electrochemical reaction. Use the values from Table 20.1 (p .909) in the text. Mn2+(aq) + Sn2+(aq) Mn(s) + Snª+(aq)
Calculate the standard cell potential for the following electrochemical reaction. Use the values from Table 20.1 (p .909) in the text. Mn2+(aq) + Sn2+(aq) Mn(s) + Snª+(aq)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![Calculate the standard cell potential for the following electrochemical reaction.
Use the values from Table 20.1 (p .909) in the text.
Mn2+(aq) + Sn²+(aq)
Mn(s) + Snª+(aq)
Answer:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7abcf093-225a-4c24-b03a-b7ef05ec57e8%2F11a8cebb-d051-45df-b479-6e32b628079c%2F2btk1k9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Calculate the standard cell potential for the following electrochemical reaction.
Use the values from Table 20.1 (p .909) in the text.
Mn2+(aq) + Sn²+(aq)
Mn(s) + Snª+(aq)
Answer:
![10:59 AM Wed Apr 13
令 2%
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Chemistry - A Molecular Approach 4th ed - Nivaldo J. Tro (Pearson-1 -
X CHM 1450 CH 19 Live Lecture Notes...
CH 18 Live Lecture Notes (W22)-1
Untitled Notebook (2)
Untitled Notebook (3)
Chemistry - A Molecular Approac... .
TABLE 19.1 Standard Electrode Potentials at 25 °C
Reduction Half-Reaction
E°(V)
F2(g) + 2 e
2 F (aq)
2.87
Weaker
Stronger
oxidizing agent
H,0,(aq) + 2 H*(aq) + 2 e
2 H20(1)
1.78
reducing agent
PbO,(s) + 4 H*(aq) + SO,²-(ag) + 2 e
PbSO,(s) + 2 H,0(1)
1.69
Mn04 (aq) + 4 H*(aq) + 3 e¯
MnO2(s) + 2 H20(1)
1.68
Mno4 (aq) + 8 H*(aq) + 5 e
Mn2+ (aq) + 4 H20(1)
1.51
Au3 + (aq) + 3 e
Au(s)
1.50
PbO2(s) + 4 H*(aq) + 2 e
Pb2+ (aq) + 2 H,0(1)
1.46
Cl2(g) + 2 e
2 СГ (ag)
1.36
Cr20,2-(aq) + 14 H*(aq) + 6 e
2 Cr3+ (aq) + 7 H20(1)
1.33
O2(g) + 4 H*(aq) + 4 e
→ 2 H20(I)
1.23
Mn02(s) + 4 H*(aq) + 2 e
Mn2+ (aq) + 2 H,0(I)
1.21
2(aq) + 3 H,0(I)
2 Br (aq)
103 (aq) + 6 H*(aq) + 5 e
1.20
Br,(1) + 2 e
1.09
VO,*(aq) + 2 H*(aq) + e
vo2+ (aq) + H20(1)
1.00
NO3 (aq) + 4 H*(aq) + 3 e
NO(g) + 2 H20(1)
0.96
CIO2 (aq)
→ Ag(s)
CIO2(g) + e
0.95
Ag* (aq) + e
0.80
Fe3+ (aq) + e
→ Fe2 + (aq)
0.77
O2(g) + 2 H*(aq) + 2 e
H2O2(aq)
0.70
Mn04 (aq) + e
Mno,2 (aq)
0.56
1(s) + 2 e
2 1 (aq)
0.54
Cu*(aq) + e
Cu(s)
0.52
02(g) + 2 H,O(1) + 4 e
4 ОН (аg)
0.40
Cu2+(ag) + 2 e
Cu(s)
0.34
So,2-(aq) + 4 H*(aq) + 2 e
H2SO3(aq) + H20(1)
0.20
Cu2+ (aq) + e
→ Cu*(aq)
0.16
Sn4+ (aq) + 2 e
Sn2+ (aq)
0.15
2 H*(aq) + 2 e
H2(g)
Fe3+ (ag) + 3 e
Fe(s)
-0.036
Pb2+ (aq) + 2 e
Pb(s)
-0.13
Sn2+ (aq) + 2 e
Sn(s)
-0.14
Ni2+ (aq) + 2 e
Ni(s)
-0.23
Cd2+(aq) + 2 e
Cd(s)
-0.40
Fe2 + (ag) + 2 e
Fe(s)
-0.45
Cr3+ (aq) + e
Cr2+ (aq)
-0.50
Cr3+ (aq) + 3 e
Cr(s)
-0.73
Zn2+(aq) + 2 e
» Zn(s)
-0.76
2 H20(1) + 2 e
» H2(g) + 2 OH (aq)
-0.83
Mn2 +(aq) + 2 e
Mn(s)
-1.18
Al3+ (aq) + 3 e
» Al(s)
-1.66
Mg2 + (aq) + 2 e
Mg(s)
-2.37
Na*(aq) + e
Na(s)
-2.71
Са2+ (ag) + 2 е
» Ca(s)
-2.76
Ba?+(ag) + 2 e
Ba(s)
-2.90
K*(aq) + e
→ K(s)
-2.92
Weaker
Stronger
reducing agent
oxidizing agent
Lit(aq) + e
» Li(s)
-3.04
940 of 1315
902
Chapter 19 Electrochemistry
LAUMPICTA ImusIaIcs How to CaicurUTe the potctlal OT an Clectrochemical cell](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7abcf093-225a-4c24-b03a-b7ef05ec57e8%2F11a8cebb-d051-45df-b479-6e32b628079c%2Fjxlwxak_processed.png&w=3840&q=75)
Transcribed Image Text:10:59 AM Wed Apr 13
令 2%
88
Chemistry - A Molecular Approach 4th ed - Nivaldo J. Tro (Pearson-1 -
X CHM 1450 CH 19 Live Lecture Notes...
CH 18 Live Lecture Notes (W22)-1
Untitled Notebook (2)
Untitled Notebook (3)
Chemistry - A Molecular Approac... .
TABLE 19.1 Standard Electrode Potentials at 25 °C
Reduction Half-Reaction
E°(V)
F2(g) + 2 e
2 F (aq)
2.87
Weaker
Stronger
oxidizing agent
H,0,(aq) + 2 H*(aq) + 2 e
2 H20(1)
1.78
reducing agent
PbO,(s) + 4 H*(aq) + SO,²-(ag) + 2 e
PbSO,(s) + 2 H,0(1)
1.69
Mn04 (aq) + 4 H*(aq) + 3 e¯
MnO2(s) + 2 H20(1)
1.68
Mno4 (aq) + 8 H*(aq) + 5 e
Mn2+ (aq) + 4 H20(1)
1.51
Au3 + (aq) + 3 e
Au(s)
1.50
PbO2(s) + 4 H*(aq) + 2 e
Pb2+ (aq) + 2 H,0(1)
1.46
Cl2(g) + 2 e
2 СГ (ag)
1.36
Cr20,2-(aq) + 14 H*(aq) + 6 e
2 Cr3+ (aq) + 7 H20(1)
1.33
O2(g) + 4 H*(aq) + 4 e
→ 2 H20(I)
1.23
Mn02(s) + 4 H*(aq) + 2 e
Mn2+ (aq) + 2 H,0(I)
1.21
2(aq) + 3 H,0(I)
2 Br (aq)
103 (aq) + 6 H*(aq) + 5 e
1.20
Br,(1) + 2 e
1.09
VO,*(aq) + 2 H*(aq) + e
vo2+ (aq) + H20(1)
1.00
NO3 (aq) + 4 H*(aq) + 3 e
NO(g) + 2 H20(1)
0.96
CIO2 (aq)
→ Ag(s)
CIO2(g) + e
0.95
Ag* (aq) + e
0.80
Fe3+ (aq) + e
→ Fe2 + (aq)
0.77
O2(g) + 2 H*(aq) + 2 e
H2O2(aq)
0.70
Mn04 (aq) + e
Mno,2 (aq)
0.56
1(s) + 2 e
2 1 (aq)
0.54
Cu*(aq) + e
Cu(s)
0.52
02(g) + 2 H,O(1) + 4 e
4 ОН (аg)
0.40
Cu2+(ag) + 2 e
Cu(s)
0.34
So,2-(aq) + 4 H*(aq) + 2 e
H2SO3(aq) + H20(1)
0.20
Cu2+ (aq) + e
→ Cu*(aq)
0.16
Sn4+ (aq) + 2 e
Sn2+ (aq)
0.15
2 H*(aq) + 2 e
H2(g)
Fe3+ (ag) + 3 e
Fe(s)
-0.036
Pb2+ (aq) + 2 e
Pb(s)
-0.13
Sn2+ (aq) + 2 e
Sn(s)
-0.14
Ni2+ (aq) + 2 e
Ni(s)
-0.23
Cd2+(aq) + 2 e
Cd(s)
-0.40
Fe2 + (ag) + 2 e
Fe(s)
-0.45
Cr3+ (aq) + e
Cr2+ (aq)
-0.50
Cr3+ (aq) + 3 e
Cr(s)
-0.73
Zn2+(aq) + 2 e
» Zn(s)
-0.76
2 H20(1) + 2 e
» H2(g) + 2 OH (aq)
-0.83
Mn2 +(aq) + 2 e
Mn(s)
-1.18
Al3+ (aq) + 3 e
» Al(s)
-1.66
Mg2 + (aq) + 2 e
Mg(s)
-2.37
Na*(aq) + e
Na(s)
-2.71
Са2+ (ag) + 2 е
» Ca(s)
-2.76
Ba?+(ag) + 2 e
Ba(s)
-2.90
K*(aq) + e
→ K(s)
-2.92
Weaker
Stronger
reducing agent
oxidizing agent
Lit(aq) + e
» Li(s)
-3.04
940 of 1315
902
Chapter 19 Electrochemistry
LAUMPICTA ImusIaIcs How to CaicurUTe the potctlal OT an Clectrochemical cell
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