Calculate the specific energy (MJ/kg) and energy density (MJ/m³) of ethane. Density o: ethane is 545 kg/m³ CH62) + 7/2 O22) Enthalpy of formation values are the following: CHoe =- 84.7 kJ/mol CO22) 2CO2(2) + 3H½O«) = -393.5 kJ/mol = -285.8 kJ/mol 0 kJ/mol SE = 5.991 MJ/kg ED = -28,334.55 MJ/cubic meter SE = -51.99 MJ/kg ED = -23,834.55 MJ/cubic meter %3D SE = -51.99 MJ/kg ED = -28,334.55 MJ/cubic meter SE = -5.199 MJ/kg ED = -2,833.55 MJ/cubic meter

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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Calculate the specific energy (MJ/kg) and energy density (MJ/m³) of ethane. Density o1
ethane is 545 kg/m³
CHoe + 7/2 O28)
Enthalpy of formation values are the following:
CH62) = - 84.7 kJ/mol
CO2)
→ 2CO2 + 3H2O¤)
= -393.5 kJ/mol
= -285.8 kJ/mol
0 kJ/mol
SE = 5.991 MJ/kg ED = -28,334.55 MJ/cubic meter
SE = -51.99 MJ/kg ED = -23,834.55 MJ/cubic meter
%3D
SE = -51.99 MJ/kg ED = -28,334.55 MJ/cubic meter
SE = -5.199 MJ/kg ED = -2,833.55 MJ/cubic meter
%3D
Transcribed Image Text:Calculate the specific energy (MJ/kg) and energy density (MJ/m³) of ethane. Density o1 ethane is 545 kg/m³ CHoe + 7/2 O28) Enthalpy of formation values are the following: CH62) = - 84.7 kJ/mol CO2) → 2CO2 + 3H2O¤) = -393.5 kJ/mol = -285.8 kJ/mol 0 kJ/mol SE = 5.991 MJ/kg ED = -28,334.55 MJ/cubic meter SE = -51.99 MJ/kg ED = -23,834.55 MJ/cubic meter %3D SE = -51.99 MJ/kg ED = -28,334.55 MJ/cubic meter SE = -5.199 MJ/kg ED = -2,833.55 MJ/cubic meter %3D
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