Calculate the spacing between contraction joints for a two lane 250 mm thick concrete road having 3.5m wide slab. Unit weight of concrete = 24 kN/m3. Ultimate stress in tension = 0.16 N/mm², coefficients of friction at interface = 1.5, and the factor of safety = 2. %3D %3D Also calculate the spacing between expansion joints if the increase in temperature is 20°C, the expansion joint gap is 24 mm and the thermal coefficient = 10 x 10-6 per C.
Calculate the spacing between contraction joints for a two lane 250 mm thick concrete road having 3.5m wide slab. Unit weight of concrete = 24 kN/m3. Ultimate stress in tension = 0.16 N/mm², coefficients of friction at interface = 1.5, and the factor of safety = 2. %3D %3D Also calculate the spacing between expansion joints if the increase in temperature is 20°C, the expansion joint gap is 24 mm and the thermal coefficient = 10 x 10-6 per C.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![4 Calculate the spacing between contraction
joints for a two lane 250 mm thick concrete
road having 3.5m wide slab. Unit weight of
concrete = 24 kN/m3. Ultimate stress in tension
= 0.16 N/mm², coefficients of friction at
interface = 1.5, and the factor of safety = 2.
Also calculate the spacing between expansion
joints if the increase in temperature is 20°C,
the expansion joint gap is 24 mm and the
thermal coefficient = 10 x 10-6 per
%3D
%3D
%3D
C.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe118c348-f1bb-4032-a4a4-ce28f93bf83b%2F63f7ebe7-1c1b-4031-9081-325270d86de9%2Ftny2iur_processed.jpeg&w=3840&q=75)
Transcribed Image Text:4 Calculate the spacing between contraction
joints for a two lane 250 mm thick concrete
road having 3.5m wide slab. Unit weight of
concrete = 24 kN/m3. Ultimate stress in tension
= 0.16 N/mm², coefficients of friction at
interface = 1.5, and the factor of safety = 2.
Also calculate the spacing between expansion
joints if the increase in temperature is 20°C,
the expansion joint gap is 24 mm and the
thermal coefficient = 10 x 10-6 per
%3D
%3D
%3D
C.
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