calculate the shear and bending moment at midspan for the beam shown The image shows a diagram of a beam subject to loads, labeled as part (b). Here's a detailed description:- **Beam Layout:** - The beam is supported on the left side by a triangular support and on the right side by a circular roller support. - The span of the beam is divided into two equal sections, each measuring 10 feet.- **Loading Conditions:** - There is a point load of 18 kips acting downward at the center of the beam. - A uniformly distributed load of 3 kips per foot is applied along the entire length of the beam.- **Dimensions:** - The total length of the beam is 20 feet, with 10 feet between each support and the point load in the center.At the bottom of the image, it states: "Calculate the shear and bending…" (the text is incomplete).This diagram is likely used for understanding shear force and bending moment calculations in structural analysis.

Consider the moment equilibrium about point A. Consider the moment equilibrium about point A. RB20=18×10+3×20×10RB=78020=39 kips Due to the symmetry of the beam. RA=RB=39 kips Consider the summation of forces in the horizontal direction. HA=0The shear force at midspan is calculated as, Vmidspan=RA-3×10-18=39 -30-18=-9 kips The bending moment at the midspan of the beam is, Mmax=RA10-310×102=3910-150=390-150=240 kips-ft Therefore, the shear force at the midspan of the beam is -9 kips bending moment at the mid span of the beam is 240 kips-ft.