Calculate the self inductance for the following cases. a)- A 3.5 m long coaxial cable with an inner radius of 0.8 mm and an outer radius of 4 mm (filled with a material of μr = 50 between conductors).

Q: An iron rod with diameter of 1.5-centimeter was formed into an almost perfect circular ring…

A: To solve these problems, we'll need to calculate the reluctance of the ring, the magnetic flux…

Q: A ferromagnetic ring has a uniform cross-sectional area of 2000 mm² and a mean circumference of 1000…

A: Cross sectional area = 2000 mm2 = 2000×10-6 m2 Mean circumference = 1000 mm = 1000×10-3 m Frequency…

Q: 2.- A cylindrical capacitor of 1 m high and 1 m diameter, is previously empty between its two…

A: 2.- A cylindrical capacitor of 1 m high and 1 m diameter, is previously empty between its two…

Q: c) Repeat parts (a) and (b) for the right slab, i- Notice that the charges on the left slab add up…

A: According to the question, we have to find an expression for the electric field with the left slab.…

Q: 2) Determine the inductance per unit length of a coaxial cable with an inner radius a and outer…

A: Given  We need to derive the inductance of a coaxial cable. Please find the below attachment for…

Solenoids

A solenoid is a common term for a telephone coil used as an electromagnet. It also refers to any device that uses a solenoid to convert electrical energy into mechanical energy. The device generates a magnetic field from an electric field and uses the magnetic field to produce precise motion. Solenoid valves are often used to change power, such as in-car transmitters or valves, such as in the fuel system.