Learning Goal:To calculate the rms speed and relative rates of effusion of gasmolecules.Part AIn a given sample of gas, the particles move at varying speeds. Theroot mean square speed (rms speed) of particles in a gas sample, u,is given by the formulaCalculate the rms speed of an oxygen gas molecule, O2, at 21.0 °C.Express your answer numerically in meters per second.3RTV Mwhere T is the Kelvin temperature, M is the molar mass in kg/mol,and R= 8.314 J/(mol - K) is the gas constant. Effusion is thegas molecules through a tiny hole into a vacuum. The rateof effusion of a gas is directly related to the rms speed of the gasmolecules, so it's inversely proportional to the square root of its mass.The rms speed is related to kinetic energy, rather than average speed,and is the speed of a molecule possessing a kinetic energy identical tothe average kinetic energy of the sample. Given its relationship to themass of the molecule, you can conclude that the lighter the moleculesof the gas, the more rapidly it effuses. Mathematically, this can be• View Available Hint(s)?escape ofm/sSubmitPrevious Answersexpressed aseffusion rate ox -X Incorrect; Try Again; 5 attempts remainingThe relative rate of effusion can be expressed in terms of molecularmasses ma and mp as

The given data : The temperature of the gas = 21°C The value of R 8.314 J/mol×K To determine =The…

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Calculate the rms speed of an oxygen gas molecule, O2, at 21.0 °C. Express your answer numerically in meters per second. • View Available Hint(s)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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