Learning Goal:To calculate the rms speed and relative rates of effusion of gasmolecules.Part AIn a given sample of gas, the particles move at varying speeds. Theroot mean square speed (rms speed) of particles in a gas sample, u,is given by the formulaCalculate the rms speed of an oxygen gas molecule, O2, at 21.0 °C.Express your answer numerically in meters per second.3RT• View Available Hint(s)U =Mwhere T is the Kelvin temperature, M is the molar mass in kg/mol,and R= 8.314 J/(mol - K) is the gas constant. Effusion is theescape of gas molecules through a tiny hole into a vacuum. The rateof effusion of a gas is directly related to the rms speed of the gasmolecules, so it's inversely proportional to the square root of its mass.The rms speed is related to kinetic energy, rather than average speed,and is the speed of athe average kinetic energy of the sample. Given its relationship to themass of the molecule, you can conclude that the lighter the moleculesof the gas, the more rapidly it effuses. Mathematically, this can beexpressed asm/smolecule possessing a kinetic energy identical toSubmitPrevious Answerseffusion rate ox -X Incorrect; Try Again; 5 attempts remainingThe relative rate of effusion can be expressed in terms of molecularmasses ma and mg as

Given : Temperature : 21.0°C OR 294 K Molar mass of oxygen molecule(O2) = 32 g/mol OR 3.2 ×…

Answered: Calculate the rms speed of an oxygen…

Calculate the rms speed of an oxygen gas molecule, 02, at 21.0 °C. Express your answer numerically in meters per second.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

Question

Learning Goal:
To calculate the rms speed and relative rates of effusion of gas
molecules.
Part A
In a given sample of gas, the particles move at varying speeds. The
root mean square speed (rms speed) of particles in a gas sample, u,
is given by the formula
Calculate the rms speed of an oxygen gas molecule, O2, at 21.0 °C.
Express your answer numerically in meters per second.
3RT
• View Available Hint(s)
U =
M
where T is the Kelvin temperature, M is the molar mass in kg/mol,
and R= 8.314 J/(mol - K) is the gas constant. Effusion is the
escape of gas molecules through a tiny hole into a vacuum. The rate
of effusion of a gas is directly related to the rms speed of the gas
molecules, so it's inversely proportional to the square root of its mass.
The rms speed is related to kinetic energy, rather than average speed,
and is the speed of a
the average kinetic energy of the sample. Given its relationship to the
mass of the molecule, you can conclude that the lighter the molecules
of the gas, the more rapidly it effuses. Mathematically, this can be
expressed as
m/s
molecule possessing a kinetic energy identical to
Submit
Previous Answers
effusion rate ox -
X Incorrect; Try Again; 5 attempts remaining
The relative rate of effusion can be expressed in terms of molecular
masses ma and mg as

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