Calculate the resonant frequency for a simple pendulum of length 1 m.
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A: Approach to solving the questionCalculated moment of inertia of the system about point A and used…
Q: The period of a simple pendulum is trebled (T' = 3T) when its initial length L is increased by 1.2 m…
A: original length = L new length (L') = L + 1.2original time period = T new time period = T' T' = 3T…
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Q: An oscillating simple pendulum has amplitude of oscillations at 0.14m and time period 2.5s.…
A: We know that,The angular frequency of the oscillation, ω=2πT Equation 1where, Time period T=2.5…
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A: The time period for pendulum is given by,, T= 2π√( l/g), which is independent of mass.
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A: We know that F = kx mg = kx k = mg/x = 10×10-3 ×9.8 / 1.9×10-2 = 5.16 N/m
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Q: A simple pendulum with a period ?=4.00 s is attached to the ceiling of an elevator which is…
A: Given information: The time period of the simple pendulum, T=4.00 s
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A: The maximum acceleration of the pendulum is calculated by using the give expression below. Here, A…
Q: As usual, the acceleration due to gravity in these problems is taken to be g = 9.80 m / s2, unless…
A: Given: The acceleration due to gravity = 9.80 m/s2 Time period of the pendulum = 0.500 s Length of…
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A: Given angular frequency of diaphragm 7.5x104rad/s.
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