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Calculate the power required to pump sulphuric acid (dynamic viscosity 0.04 Pa s, relative density 1.83) at 45 L s from a supply tank through a glass-lined 150 mm diameter pipe, 18 m long, into a storage tank. The liquid level in the storage tank is 6 m above that in the supply tank. For laminar flow f 16/Re; for turbulent flow f= 0.0014(1 + 100*Re13) if Re < 107. Take all losses into account.

Calculate the power required to pump sulphuric acid (dynamic viscosity 0.04 Pa s, relative density 1.83) at 45 L s from a supply tank through a glass-lined 150 mm diameter pipe, 18 m long, into a storage tank. The liquid level in the storage tank is 6 m above that in the supply tank. For laminar flow f 16/Re; for turbulent flow f= 0.0014(1 + 100*Re13) if Re < 107. Take all losses into account.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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**Problem Statement:** Calculate the power required to pump sulphuric acid (dynamic viscosity 0.04 Pa·s, relative density 1.83) at 45 L·s⁻¹ from a supply tank through a glass-lined 150 mm diameter pipe, 18 m long, into a storage tank. The liquid level in the storage tank is 6 m above that in the supply tank. For laminar flow, \( f = \frac{16}{Re} \); for turbulent flow \( f = 0.0014(1 + 100 \times Re^{-1/3}) \) if \( Re < 10^7 \). Take all losses into account. **Explanation of Formulae and Terms:** - **Dynamic Viscosity (\(\mu\))**: A measure of a fluid's resistance to flow, given as 0.04 Pa·s. - **Relative Density**: The ratio of the density of the fluid to the density of a reference substance (usually water), given as 1.83. - **Flow Rate**: Given as 45 L·s⁻¹ (liters per second). - **Pipe Specifications**: - Diameter: 150 mm - Length: 18 m - **Elevation Difference**: 6 m (height difference between liquid levels in the tanks). - **Reynolds Number (\(Re\))**: A dimensionless quantity used to predict flow patterns in different fluid flow situations. - **Friction Factor (\(f\))**: - **Laminar Flow**: \( f = \frac{16}{Re} \) - **Turbulent Flow**: \( f = 0.0014(1 + 100 \times Re^{-1/3}) \) provided \( Re < 10^7 \). The problem involves determining the power needed to overcome resistances and elevate the fluid, using the given equations for friction factors in laminar and turbulent flow regimes.
Transcribed Image Text:**Problem Statement:** Calculate the power required to pump sulphuric acid (dynamic viscosity 0.04 Pa·s, relative density 1.83) at 45 L·s⁻¹ from a supply tank through a glass-lined 150 mm diameter pipe, 18 m long, into a storage tank. The liquid level in the storage tank is 6 m above that in the supply tank. For laminar flow, \( f = \frac{16}{Re} \); for turbulent flow \( f = 0.0014(1 + 100 \times Re^{-1/3}) \) if \( Re < 10^7 \). Take all losses into account. **Explanation of Formulae and Terms:** - **Dynamic Viscosity (\(\mu\))**: A measure of a fluid's resistance to flow, given as 0.04 Pa·s. - **Relative Density**: The ratio of the density of the fluid to the density of a reference substance (usually water), given as 1.83. - **Flow Rate**: Given as 45 L·s⁻¹ (liters per second). - **Pipe Specifications**: - Diameter: 150 mm - Length: 18 m - **Elevation Difference**: 6 m (height difference between liquid levels in the tanks). - **Reynolds Number (\(Re\))**: A dimensionless quantity used to predict flow patterns in different fluid flow situations. - **Friction Factor (\(f\))**: - **Laminar Flow**: \( f = \frac{16}{Re} \) - **Turbulent Flow**: \( f = 0.0014(1 + 100 \times Re^{-1/3}) \) provided \( Re < 10^7 \). The problem involves determining the power needed to overcome resistances and elevate the fluid, using the given equations for friction factors in laminar and turbulent flow regimes.
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