Calculate the pH when 62.0 mL of 0.250 M HCI is mixed with 40.0 mL of 0.150 M Ca(OH)2.

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**Problem Statement:**

Calculate the pH when 62.0 mL of 0.250 M HCl is mixed with 40.0 mL of 0.150 M Ca(OH)₂.

**Solution Approach:**

1. **Determine Moles:**
   - Find the moles of HCl:
     \[
     \text{Moles of HCl} = 62.0\, \text{mL} \times 0.250\, \text{M} \times \frac{1\, \text{L}}{1000\, \text{mL}}
     \]
   - Find the moles of Ca(OH)₂:
     \[
     \text{Moles of Ca(OH)₂} = 40.0\, \text{mL} \times 0.150\, \text{M} \times \frac{1\, \text{L}}{1000\, \text{mL}}
     \]

2. **Determine Reaction:**
   - HCl is a strong acid and Ca(OH)₂ is a strong base. The balanced reaction is:
     \[
     2 \text{HCl} + \text{Ca(OH)}_2 \rightarrow 2 \text{H}_2\text{O} + \text{CaCl}_2
     \]

3. **Determine Limiting Reagent:**
   - Calculate the moles of H⁺ from HCl.
   - Calculate the moles of OH⁻ from Ca(OH)₂ (note: 1 mole of Ca(OH)₂ provides 2 moles of OH⁻).
   - The limiting reagent will determine the leftover moles of either H⁺ or OH⁻.

4. **Calculate pH or pOH:**
   - If H⁺ is leftover, calculate pH using:
     \[
     \text{pH} = -\log[\text{H}^+]
     \]
   - If OH⁻ is leftover, calculate pOH and then pH using:
     \[
     \text{pOH} = -\log[\text{OH}^-]
     \]
     \[
     \text{pH} = 14 - \text{pOH}
     \]

5. **Determine Final Concentration:**
   - Consider total volume
Transcribed Image Text:**Problem Statement:** Calculate the pH when 62.0 mL of 0.250 M HCl is mixed with 40.0 mL of 0.150 M Ca(OH)₂. **Solution Approach:** 1. **Determine Moles:** - Find the moles of HCl: \[ \text{Moles of HCl} = 62.0\, \text{mL} \times 0.250\, \text{M} \times \frac{1\, \text{L}}{1000\, \text{mL}} \] - Find the moles of Ca(OH)₂: \[ \text{Moles of Ca(OH)₂} = 40.0\, \text{mL} \times 0.150\, \text{M} \times \frac{1\, \text{L}}{1000\, \text{mL}} \] 2. **Determine Reaction:** - HCl is a strong acid and Ca(OH)₂ is a strong base. The balanced reaction is: \[ 2 \text{HCl} + \text{Ca(OH)}_2 \rightarrow 2 \text{H}_2\text{O} + \text{CaCl}_2 \] 3. **Determine Limiting Reagent:** - Calculate the moles of H⁺ from HCl. - Calculate the moles of OH⁻ from Ca(OH)₂ (note: 1 mole of Ca(OH)₂ provides 2 moles of OH⁻). - The limiting reagent will determine the leftover moles of either H⁺ or OH⁻. 4. **Calculate pH or pOH:** - If H⁺ is leftover, calculate pH using: \[ \text{pH} = -\log[\text{H}^+] \] - If OH⁻ is leftover, calculate pOH and then pH using: \[ \text{pOH} = -\log[\text{OH}^-] \] \[ \text{pH} = 14 - \text{pOH} \] 5. **Determine Final Concentration:** - Consider total volume
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