Calculate the pH of the solution after the following addition to the 42.0 mL of 0.135 M HCl: B) 20.0 mL 0.150 M NaOH Step 2: Identify the initial moles of each reactant. Round each answer to FIVE places past the decimal. .00567 .00300 Step 4: What is the pH? Round your answer to TWO places past the decimal. OH is present in excess. o moles of excess reactant: type your answer... mol o total solution volume after base addition: type your answer... • Because this solution contains choose your answer... . On the titration curve, this is at/in the excess SA region (not mol H+ (from HCI) Step 3: Determine what is present after neutralization, and identify the conditions of this solution. Round moles to FIVE places past the decimal and volume to FOUR places past the decimal. mol OH (from NaOH) the solving method entails using choose your answer... type your answer...

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Calculate the pH of the solution after the following addition to the 42.0 mL of 0.135 M HCI:
B) 20.0 mL 0.150 M NaOH
Step 2: Identify the initial moles of each reactant.
Round each answer to FIVE places past the decimal.
.00567
.00300
Step 4: What is the pH?
Round your answer to TWO places past the decimal.
mol H+ (from HCI)
Step 3: Determine what is present after neutralization, and identify the conditions of this solution.
Round moles to FIVE places past the decimal and volume to FOUR places past the decimal.
mol OH (from NaOH)
OH
is present in excess.
o moles of excess reactant:
type your answer...
o total solution volume after base addition: type your answer...
• Because this solution contains choose your answer... ✓, the solving method entails using choose your answer...
• On the titration curve, this is at/in the excess SA region (not
mol
type your answer...
L
Transcribed Image Text:Calculate the pH of the solution after the following addition to the 42.0 mL of 0.135 M HCI: B) 20.0 mL 0.150 M NaOH Step 2: Identify the initial moles of each reactant. Round each answer to FIVE places past the decimal. .00567 .00300 Step 4: What is the pH? Round your answer to TWO places past the decimal. mol H+ (from HCI) Step 3: Determine what is present after neutralization, and identify the conditions of this solution. Round moles to FIVE places past the decimal and volume to FOUR places past the decimal. mol OH (from NaOH) OH is present in excess. o moles of excess reactant: type your answer... o total solution volume after base addition: type your answer... • Because this solution contains choose your answer... ✓, the solving method entails using choose your answer... • On the titration curve, this is at/in the excess SA region (not mol type your answer... L
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