Calculate the pH of the above buffer after 10.00 mL of 1.000 M NaOH (0.01000 mol OH-1) was added to 1.000 L of the buffer solution. The new concentrations are [HC2H302] = 0.4900 M and [C2H3O21] = 0.7100 M. The K, = 1.60 x 10-5. everything is based upon the acid dissolving in water: HC2H3O2 + H20 <-> C;H3O21 + H30+1 K = solve for [H30*1] then put in the numbers Ka [ [H3O*l] = [H3O*'] = pH = - log a. H30*1 b. Он1 c. H2C6H6O6 d. HCGH6O61 e. HSO31 f. SO3 2 g. H2SO3 h. HC2H3O2 i. C2H3O21 j. H2S k. HS-1 I. S2 n. X-1 o. 1 р. 2 m. HX q. 3 r. 0.5000 s. 5.5 X 10-5 t. 3.5 X 10-4 u. 8.00 x 10:5 v. 1.75 x 10-6 w. 1.11 x 10-8 x. 5.5 x 10-2 у. О.7000 z. 1.60 x 10:5 аа. 1.143 х 10-5 bb. 0.4900 сс. 1.104 х 10-5 dd. 0.7100 ее. 1.26 х 10-5 ff. 4.901 gg. 7.93 hh. 4.942 ii. 4.957
Calculate the pH of the above buffer after 10.00 mL of 1.000 M NaOH (0.01000 mol OH-1) was added to 1.000 L of the buffer solution. The new concentrations are [HC2H302] = 0.4900 M and [C2H3O21] = 0.7100 M. The K, = 1.60 x 10-5. everything is based upon the acid dissolving in water: HC2H3O2 + H20 <-> C;H3O21 + H30+1 K = solve for [H30*1] then put in the numbers Ka [ [H3O*l] = [H3O*'] = pH = - log a. H30*1 b. Он1 c. H2C6H6O6 d. HCGH6O61 e. HSO31 f. SO3 2 g. H2SO3 h. HC2H3O2 i. C2H3O21 j. H2S k. HS-1 I. S2 n. X-1 o. 1 р. 2 m. HX q. 3 r. 0.5000 s. 5.5 X 10-5 t. 3.5 X 10-4 u. 8.00 x 10:5 v. 1.75 x 10-6 w. 1.11 x 10-8 x. 5.5 x 10-2 у. О.7000 z. 1.60 x 10:5 аа. 1.143 х 10-5 bb. 0.4900 сс. 1.104 х 10-5 dd. 0.7100 ее. 1.26 х 10-5 ff. 4.901 gg. 7.93 hh. 4.942 ii. 4.957
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
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![Calculate the pH of the above buffer after 10.00 mL of 1.000 M NaOH (0.01000 mol OH-1) was added to 1.000 L of the buffer solution. The new concentrations
are [HC,H3O2] = 0.4900 M and [C2H3O21] = 0.7100 M. The Ką = 1.60 x 10-5.
everything is based upon the acid dissolving in water:
HC2H3O2
+ H20 <-> C2H3O21 + H3O*1
[h
Ka
[ i
solve for [H3O+l] then put in the numbers
Ka [
[H3O+'] =
[
[H3O*1] =
pH = - log
%3D
f. SO3?
a. H30+1
b. Он1
c. H2C6H6O6
d. HCGH,061
е. HSO31
-2
g. H2SO3
h. HC2H3O2
i. C,H3O21
j. H2S
k. HS-1
I. s2
m. HX
п. X1
О. 1
р. 2
q. 3
r. 0.5000
s. 5.5 X 10-5
t. 3.5 X 10-4
u. 8.00 x 10-5
v. 1.75 x 10-6
w. 1.11 x 108
х. 5.5 х 102
у. О.7000
z. 1.60 x 10-5
аа. 1.143 х 10-5
bb. 0.4900
сс. 1.104 х 10-5
dd. 0.7100
ее. 1.26 х 10-5 ff. 4.901
gg. 7.93
hh. 4.942
ii. 4.957](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F30cedfe8-9c5c-4d68-af83-765787417218%2F0006c3d8-0374-4455-8bcf-e61f72079324%2Fju6d7a8_processed.png&w=3840&q=75)
Transcribed Image Text:Calculate the pH of the above buffer after 10.00 mL of 1.000 M NaOH (0.01000 mol OH-1) was added to 1.000 L of the buffer solution. The new concentrations
are [HC,H3O2] = 0.4900 M and [C2H3O21] = 0.7100 M. The Ką = 1.60 x 10-5.
everything is based upon the acid dissolving in water:
HC2H3O2
+ H20 <-> C2H3O21 + H3O*1
[h
Ka
[ i
solve for [H3O+l] then put in the numbers
Ka [
[H3O+'] =
[
[H3O*1] =
pH = - log
%3D
f. SO3?
a. H30+1
b. Он1
c. H2C6H6O6
d. HCGH,061
е. HSO31
-2
g. H2SO3
h. HC2H3O2
i. C,H3O21
j. H2S
k. HS-1
I. s2
m. HX
п. X1
О. 1
р. 2
q. 3
r. 0.5000
s. 5.5 X 10-5
t. 3.5 X 10-4
u. 8.00 x 10-5
v. 1.75 x 10-6
w. 1.11 x 108
х. 5.5 х 102
у. О.7000
z. 1.60 x 10-5
аа. 1.143 х 10-5
bb. 0.4900
сс. 1.104 х 10-5
dd. 0.7100
ее. 1.26 х 10-5 ff. 4.901
gg. 7.93
hh. 4.942
ii. 4.957
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