Calculate the pH of a solution that is 0.0330 M in a. NaH,PO4 (Kal = 7.11 x 10-3, K,2 = 6.32 × 10-8). %3D pH = b. NaHSO3 (Kal = 1.23 x 10-2, K2 = 6.60 × 10-8). pH = H2NC2 H4NH3+Cl¯ (Kal = 1.42 × 10-7, K.2 с. = 1.18 x 10-10). pH =
Calculate the pH of a solution that is 0.0330 M in a. NaH,PO4 (Kal = 7.11 x 10-3, K,2 = 6.32 × 10-8). %3D pH = b. NaHSO3 (Kal = 1.23 x 10-2, K2 = 6.60 × 10-8). pH = H2NC2 H4NH3+Cl¯ (Kal = 1.42 × 10-7, K.2 с. = 1.18 x 10-10). pH =
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Calculate the pH of a solution that is 0.0330 M in:**
a. **NaH₂PO₄** \((K_{a1} = 7.11 \times 10^{-3}, \ K_{a2} = 6.32 \times 10^{-8})\).
pH = \_\_\_
b. **NaHSO₃** \((K_{a1} = 1.23 \times 10^{-2}, \ K_{a2} = 6.60 \times 10^{-8})\).
pH = \_\_\_
c. **H₂NC₂H₄NH₃⁺Cl⁻** \((K_{a1} = 1.42 \times 10^{-7}, \ K_{a2} = 1.18 \times 10^{-10})\).
pH = \_\_\_
---
**Instructions for Calculating pH:**
- Determine the dominant acidic or basic species in the solution.
- Use the appropriate equilibrium expression and initial concentrations to calculate the concentration of hydrogen ions \([H⁺]\) or hydroxide ions \([OH⁻]\).
- Convert the concentration to pH using:
- \( \text{pH} = -\log[H⁺] \)
- For solutions with multiple dissociation steps, you may need to consider each equilibrium step to determine the final pH accurately.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb2c2bfdd-c795-4c13-bc09-4b743040f0d9%2F24dfd095-aa19-4d93-9023-ec4e28a73a77%2Fcujmzmo_processed.png&w=3840&q=75)
Transcribed Image Text:**Calculate the pH of a solution that is 0.0330 M in:**
a. **NaH₂PO₄** \((K_{a1} = 7.11 \times 10^{-3}, \ K_{a2} = 6.32 \times 10^{-8})\).
pH = \_\_\_
b. **NaHSO₃** \((K_{a1} = 1.23 \times 10^{-2}, \ K_{a2} = 6.60 \times 10^{-8})\).
pH = \_\_\_
c. **H₂NC₂H₄NH₃⁺Cl⁻** \((K_{a1} = 1.42 \times 10^{-7}, \ K_{a2} = 1.18 \times 10^{-10})\).
pH = \_\_\_
---
**Instructions for Calculating pH:**
- Determine the dominant acidic or basic species in the solution.
- Use the appropriate equilibrium expression and initial concentrations to calculate the concentration of hydrogen ions \([H⁺]\) or hydroxide ions \([OH⁻]\).
- Convert the concentration to pH using:
- \( \text{pH} = -\log[H⁺] \)
- For solutions with multiple dissociation steps, you may need to consider each equilibrium step to determine the final pH accurately.
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