Calculate the pH and the Ka for HC₂H3O2 if in a 1.0000 M solution of HC₂H3O2 in water there is 0.9960 M HC₂H3O2. Usethe data provided.HC₂H3O2 + H₂O C₂H30₂¹ + H3O+1start:1.00000 M0equil:0.99600 M0.0040 M0.0040 M0.00400 MM.The amount of HC₂H3O2 that was converted into product ismol of C₂H30₂1 andThe stoichiometry tells us that 1 mol HC₂H3O2 will give usmol of H30+1Thus,M HC₂H3O2 will giveM H30+1Because we know the [H3O+¹] we can calculate the pH = -log([I][[])(c. 0.0040Ka(Ka =a. acetich. CaCO3(s)-10. H₂PO4-¹v. H₂CO3bb. 0.0077ii. 1.60 x 10-5b. 0.9960i. OH-1-2-3p. CO3-²W. PO4³CC. 3jj. 2.398j. H30+1q. HCO3-1x. HC₂H3O2dd. 2d. Al+3kk. 0.05656K. SO4²r. H₂Sy. C₂H30₂-1ee. 1e. CO₂I. Mg+2S. HS-1ff. 0.0154f. CaF2(aq)m. Cl-1t. S-2z. 1 x 10-14gg. 3.95 x 10-3M C₂H30₂¹ and|) =g. HF(aq)n. HPO4²u. H₂O(liq)aa. 0.9923hh. 1.84 x 10-6ii

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Calculate the pH and the Ka for HC₂H3O2 if in a 1.0000 M solution of HC₂H3O2 in water there is 0.9960 M HC₂H3O2. Use the data provided. HC₂H3O2 + H₂O C₂H3021 + H30+1 start: 1.00000 M 0 0 equil: 0.99600 M 0.0040 M 0.0040 M 0.00400 M The amount of HC₂H3O2 that was converted into product is M. The stoichiometry tells us that 1 mol HC₂H3O2 will give us mol of C₂H302¹ and mol of H30+1 Thus, M HC₂H302 will give M H30+1 Because we know the [H3O+¹] can calculate the pH [ I c. 0.0040 Ka = Ka a. acetic b. 0.9960 h. CaCO3(s) i. OH-1 0. H₂PO4¹ p. CO3² v. H₂CO3 W. PO43 bb. 0.0077 cc. 3 ii. 1.60 x 10-5 jj. 2.398 j. H30+1 q. HCO3-1 x. HC₂H3O2 dd. 2 d. Al+3 kk. 0.05656 = -log( K. SO4² r. H₂S y. C₂H30₂-1 ee. 1 e. CO₂ 1. Mg+2 s. HS-1 ff. 0.0154 f. CaF2(aq) m. Cl-1 t. S-2 z. 1x 10-14 gg. 3.95 x 10-3 M C₂H30₂¹ and )= g. HF(aq) n. HPO42 u. H₂O(liq) aa. 0.9923 hh. 1.84 x 10-6 ici

Calculate the pH and the Ka for HC₂H3O2 if in a 1.0000 M solution of HC₂H3O2 in water there is 0.9960 M HC₂H3O2. Use the data provided. HC₂H3O2 + H₂O C₂H3021 + H30+1 start: 1.00000 M 0 0 equil: 0.99600 M 0.0040 M 0.0040 M 0.00400 M The amount of HC₂H3O2 that was converted into product is M. The stoichiometry tells us that 1 mol HC₂H3O2 will give us mol of C₂H302¹ and mol of H30+1 Thus, M HC₂H302 will give M H30+1 Because we know the [H3O+¹] can calculate the pH [ I c. 0.0040 Ka = Ka a. acetic b. 0.9960 h. CaCO3(s) i. OH-1 0. H₂PO4¹ p. CO3² v. H₂CO3 W. PO43 bb. 0.0077 cc. 3 ii. 1.60 x 10-5 jj. 2.398 j. H30+1 q. HCO3-1 x. HC₂H3O2 dd. 2 d. Al+3 kk. 0.05656 = -log( K. SO4² r. H₂S y. C₂H30₂-1 ee. 1 e. CO₂ 1. Mg+2 s. HS-1 ff. 0.0154 f. CaF2(aq) m. Cl-1 t. S-2 z. 1x 10-14 gg. 3.95 x 10-3 M C₂H30₂¹ and )= g. HF(aq) n. HPO42 u. H₂O(liq) aa. 0.9923 hh. 1.84 x 10-6 ici

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter14: Acids And Bases

Section: Chapter Questions

Problem 32QRT

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