Calculate the number of moles of HI that are at equilibrium with 1.25 mol of H₂ and 1.25 mol of 12 in a 5.00-L flask at 448 °C. H₂+12=2HI Kc = 50.2 at 448 °C

Chemistry for Engineering Students
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Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.37PAE: Again the experiment in Exercise 12.33 was redesigned. This time, 0.15 mol each of N, and O2 was...
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### Equilibrium Calculation Example

**Problem Statement:**
Calculate the number of moles of HI that are at equilibrium with 1.25 mol of H₂ and 1.25 mol of I₂ in a 5.00-L flask at 448 °C.

The balanced chemical equation for the reaction is:

\[ \text{H}_2 + \text{I}_2 \rightleftharpoons 2\text{HI} \]

The equilibrium constant (\( K_c \)) for this reaction at 448 °C is given as:

\[ K_c = 50.2 \text{ at 448 °C} \]

In this problem, we need to find the equilibrium concentration of HI in the flask.
Transcribed Image Text:### Equilibrium Calculation Example **Problem Statement:** Calculate the number of moles of HI that are at equilibrium with 1.25 mol of H₂ and 1.25 mol of I₂ in a 5.00-L flask at 448 °C. The balanced chemical equation for the reaction is: \[ \text{H}_2 + \text{I}_2 \rightleftharpoons 2\text{HI} \] The equilibrium constant (\( K_c \)) for this reaction at 448 °C is given as: \[ K_c = 50.2 \text{ at 448 °C} \] In this problem, we need to find the equilibrium concentration of HI in the flask.
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