Calculate the moles of the limiting reagent for the following reaction: oxidation of cyclododecanol to cyclododecanone.    0.2093 grams of Cyclododecanol 0.5 mL of acetone 0.20 mL of Glacial acetic acid  2.0 mL of bleach Final weight of cyclododecanone = 0.0578 g

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A: The given experiment includes the synthesis of ethyl acetate from acetic acid Given that, 13.9 g of…

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Q: A student adds 190 g of c7h6o3 to an excess of c4h6o3, producing c9h8o4 and c2h4o2. Write and…

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Q: Combustion reactions are exothernic. The heat of reaction for the combustion of cyclohexane, CH2, is…

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Q: Calculate the theoretical yield in grams of 3,5-diiodotyrosine (molar mass 432.98 g/mol) that can be…

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Q: How many moles are contained in each number of grams of fructose (C6H1206, molar mass 180.2 g/mol),…

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Q: If the enthalpy of C12H22O11 combustion is said to be -5.65 x 103 kJ/mol, calculate the mass of…

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Q: 138.16 g/mol) and 0.93 g of benzyl bromide (MW=171.03 g/mol) for the following reaction, which one…

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Q: Calculate the percent yield and theoretical yield for the following reaction: oxidation of…

A: Given data  0.2093 grams of Cyclododecanol 0.5 mL of acetone 0.20 mL of Glacial acetic acid 2.0 mL…

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Alkanes and Cycloalkanes

Alkanes are saturated organic compounds which are made up of C and H atoms. Alkanes have the general formula of CnH2n+2. Alkane contains sp3 hybridized carbon atoms with four sigmas (σ) bonds & every hydrogen atom is connected with one of the carbon atoms. The size of the alkane could be determined by the number of carbon atoms located in it.