Calculate the moles of the limiting reagent for the following reaction: oxidation of cyclododecanol to cyclododecanone.    0.2093 grams of Cyclododecanol 0.5 mL of acetone 0.20 mL of Glacial acetic acid  2.0 mL of bleach Final weight of cyclododecanone = 0.0578 g

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Calculate the moles of the limiting reagent for the following reaction: oxidation of cyclododecanol to cyclododecanone. 

 

0.2093 grams of Cyclododecanol

0.5 mL of acetone

0.20 mL of Glacial acetic acid 

2.0 mL of bleach

Final weight of cyclododecanone = 0.0578 g



Expert Solution
Step 1

Given:

Mass of Cyclododecanol = 0.2093 g

Volume of acetone = 0.5 mL

Volume of Glacial acetic acid =0.20 mL

Volume of bleach, NaClO = 2.0 mL

Mass of product, cyclododecanone = 0.0578 g

To calculate:

To calculate the moles of the limiting reagent for the following reaction:

oxidation of cyclododecanol to cyclododecanone. 

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