Calculate the Molecular weight of a 3.39 liter sample of an unknown gas with a mass of 68.87 grams at STP

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
icon
Concept explainers
Question
**Problem Statement:**

Calculate the molecular weight of a 3.39-liter sample of an unknown gas with a mass of 68.87 grams at STP (Standard Temperature and Pressure).

**Description:**

In this problem, you are given:
- Volume of the gas sample: 3.39 liters
- Mass of the gas sample: 68.87 grams
- Conditions: Standard Temperature and Pressure (STP), which means the temperature is 273.15 K (0°C) and the pressure is 1 atmosphere (atm).

To calculate the molecular weight (also known as molar mass) of the gas, you can use the Ideal Gas Law in conjunction with the definition of molecular weight.

**Relevant Formulas:**

1. **Ideal Gas Law:**
   \[
   PV = nRT
   \]
   Where:
   - \( P \) is the pressure of the gas (in atm),
   - \( V \) is the volume of the gas (in liters),
   - \( n \) is the amount of substance (in moles),
   - \( R \) is the gas constant (0.0821 L·atm/(K·mol)),
   - \( T \) is the temperature (in Kelvin).

2. **Molecular Weight Formula:**
   \[
   \text{Molecular Weight} = \frac{\text{Mass}}{n}
   \]
   - Where the mass is given in grams, and \( n \) (number of moles) can be derived from the Ideal Gas Law.

3. At STP (Standard Temperature and Pressure):
   \[
   1 \text{ mole of an ideal gas occupies 22.414 liters}
   \]
   Based on this, the number of moles (\( n \)) can also be directly determined as:
   \[
   n = \frac{V}{22.414 \text{ L}}
   \]

**Steps to Solve:**
1. Calculate the number of moles (\( n \)) of the gas using its volume at STP:
   \[
   n = \frac{3.39 \text{ L}}{22.414 \text{ L/mol}}
   \]

2. Substitute \( n \) into the molecular weight formula to find the molecular weight.

**Solution Approach:**

1. Compute \( n \):
   \[
   n = \frac{3
Transcribed Image Text:**Problem Statement:** Calculate the molecular weight of a 3.39-liter sample of an unknown gas with a mass of 68.87 grams at STP (Standard Temperature and Pressure). **Description:** In this problem, you are given: - Volume of the gas sample: 3.39 liters - Mass of the gas sample: 68.87 grams - Conditions: Standard Temperature and Pressure (STP), which means the temperature is 273.15 K (0°C) and the pressure is 1 atmosphere (atm). To calculate the molecular weight (also known as molar mass) of the gas, you can use the Ideal Gas Law in conjunction with the definition of molecular weight. **Relevant Formulas:** 1. **Ideal Gas Law:** \[ PV = nRT \] Where: - \( P \) is the pressure of the gas (in atm), - \( V \) is the volume of the gas (in liters), - \( n \) is the amount of substance (in moles), - \( R \) is the gas constant (0.0821 L·atm/(K·mol)), - \( T \) is the temperature (in Kelvin). 2. **Molecular Weight Formula:** \[ \text{Molecular Weight} = \frac{\text{Mass}}{n} \] - Where the mass is given in grams, and \( n \) (number of moles) can be derived from the Ideal Gas Law. 3. At STP (Standard Temperature and Pressure): \[ 1 \text{ mole of an ideal gas occupies 22.414 liters} \] Based on this, the number of moles (\( n \)) can also be directly determined as: \[ n = \frac{V}{22.414 \text{ L}} \] **Steps to Solve:** 1. Calculate the number of moles (\( n \)) of the gas using its volume at STP: \[ n = \frac{3.39 \text{ L}}{22.414 \text{ L/mol}} \] 2. Substitute \( n \) into the molecular weight formula to find the molecular weight. **Solution Approach:** 1. Compute \( n \): \[ n = \frac{3
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Knowledge Booster
Ideal and Real Gases
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY