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Calculate the molarity of a solution made by dissolving 1.834 g of sodium hydroxide in enough water to make 300. mL of solution. O.137 M .153 M O.115 M O.173 M

Calculate the molarity of a solution made by dissolving 1.834 g of sodium hydroxide in enough water to make 300. mL of solution. O.137 M .153 M O.115 M O.173 M

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Calculate the molarity of a solution made my dissolving 1.834g of sodium hydroxide in enough water to make 300.mL of solution.
**Problem Statement:** Calculate the molarity of a solution made by dissolving 1.834 g of sodium hydroxide in enough water to make 300. mL of solution. **Answer Choices:** - ○ 0.137 M - ○ 0.153 M - ○ 0.115 M - ○ 0.173 M **Explanation:** To solve this problem, follow these steps: 1. **Determine the molar mass of sodium hydroxide (NaOH):** - Sodium (Na): approximately 23 g/mol - Oxygen (O): approximately 16 g/mol - Hydrogen (H): approximately 1 g/mol - Total molar mass = 23 + 16 + 1 = 40 g/mol 2. **Calculate the moles of sodium hydroxide:** - Moles = mass / molar mass - Moles = 1.834 g / 40 g/mol = 0.04585 mol 3. **Convert the volume of solution from milliliters to liters:** - Volume in liters = 300 mL × (1 L / 1000 mL) = 0.3 L 4. **Calculate the molarity (M), which is moles of solute per liter of solution:** - Molarity (M) = moles / volume in liters - Molarity = 0.04585 mol / 0.3 L = 0.153 M Thus, the correct answer is 0.153 M.
Transcribed Image Text:**Problem Statement:** Calculate the molarity of a solution made by dissolving 1.834 g of sodium hydroxide in enough water to make 300. mL of solution. **Answer Choices:** - ○ 0.137 M - ○ 0.153 M - ○ 0.115 M - ○ 0.173 M **Explanation:** To solve this problem, follow these steps: 1. **Determine the molar mass of sodium hydroxide (NaOH):** - Sodium (Na): approximately 23 g/mol - Oxygen (O): approximately 16 g/mol - Hydrogen (H): approximately 1 g/mol - Total molar mass = 23 + 16 + 1 = 40 g/mol 2. **Calculate the moles of sodium hydroxide:** - Moles = mass / molar mass - Moles = 1.834 g / 40 g/mol = 0.04585 mol 3. **Convert the volume of solution from milliliters to liters:** - Volume in liters = 300 mL × (1 L / 1000 mL) = 0.3 L 4. **Calculate the molarity (M), which is moles of solute per liter of solution:** - Molarity (M) = moles / volume in liters - Molarity = 0.04585 mol / 0.3 L = 0.153 M Thus, the correct answer is 0.153 M.
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