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Calculate the mean and standard deviation of the number dental fillings in the sample of 8 patients: 0, 0, 1, 1, 2, 3, 3, 6, 7 Show your work below.

Calculate the mean and standard deviation of the number dental fillings in the sample of 8 patients: 0, 0, 1, 1, 2, 3, 3, 6, 7 Show your work below.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Can it please be checked? I need to find the mean and standard deviation. I don't know if 8 sample and 9 numbers is tricky
Problem 4 Calculate the mean and standard deviation of the number of dental fillings in the sample of 8 patients: \(0, \ 0, \ 1, \ 1, \ 2, \ 3, \ 6, \ 7\) Show your work below. \[ \begin{array}{ccc} x & \text{dev}(x-2.56) & \text{Dev}^2 \\ \hline 0 & 0 - 2.56 = -2.56 & 6.55 \\ 0 & 0 - 2.56 = -2.56 & 6.55 \\ 1 & 1 - 2.56 = -1.56 & 2.4 \ 50/8 \\ 1 & 1 - 2.56 = -1.56 & 2.4 \ SR-6.25 \\ 2 & 2 - 2.56 = -.56 & 0.3 \ 9 \\ 3 & 3 - 2.56 = 0.44 & 0.19 \\ 3 & 3 - 2.56 = 0.44 & 0.19 \\ 6 & 6 - 2.56 = 3.44 & 11.8 \\ 7 & 7 - 2.56 = 4.44 & 19.7 \\ \hline & \text{Mean} = 2.56 & 50.08 \ \text{St Dev} = 2.5 \\ \end{array} \] Part 2 (Multiple choice)
Transcribed Image Text:Problem 4 Calculate the mean and standard deviation of the number of dental fillings in the sample of 8 patients: \(0, \ 0, \ 1, \ 1, \ 2, \ 3, \ 6, \ 7\) Show your work below. \[ \begin{array}{ccc} x & \text{dev}(x-2.56) & \text{Dev}^2 \\ \hline 0 & 0 - 2.56 = -2.56 & 6.55 \\ 0 & 0 - 2.56 = -2.56 & 6.55 \\ 1 & 1 - 2.56 = -1.56 & 2.4 \ 50/8 \\ 1 & 1 - 2.56 = -1.56 & 2.4 \ SR-6.25 \\ 2 & 2 - 2.56 = -.56 & 0.3 \ 9 \\ 3 & 3 - 2.56 = 0.44 & 0.19 \\ 3 & 3 - 2.56 = 0.44 & 0.19 \\ 6 & 6 - 2.56 = 3.44 & 11.8 \\ 7 & 7 - 2.56 = 4.44 & 19.7 \\ \hline & \text{Mean} = 2.56 & 50.08 \ \text{St Dev} = 2.5 \\ \end{array} \] Part 2 (Multiple choice)
## Statistical Data Analysis ### Dataset and Calculations This table presents a dataset along with calculations for each data point, showing deviations from the mean and the squared deviations. #### Table Explanation | x | dev(x-2.56) | Dev^2 | |---|-------------|-------| | 0 | 0 - 2.56 = -2.56 | 6.55 | | 0 | 0 - 2.56 = -2.56 | 6.55 | | 1 | 1 - 2.56 = -1.56 | 2.4 | | 1 | 1 - 2.56 = -1.56 | 2.4 | | 2 | 2 - 2.56 = -0.56 | 0.3 | | 3 | 3 - 2.56 = 0.44 | 0.19 | | 3 | 3 - 2.56 = 0.44 | 0.19 | | 6 | 6 - 2.56 = 3.44 | 11.8 | | 7 | 7 - 2.56 = 4.44 | 19.7 | - **Total of x values**: 2.56 - **Sum of squared deviations**: 50.08 #### Calculations - **Mean (Average):** The mean of the dataset is given as 2.56. - **Sum of squares (Dev^2):** Total sums of the squared deviations is 50.08. - **Square root of the total squared deviations and IQR calculations:** - Square root of 6.25 isolated in the table. - Mean and standard deviation are shown as Mean = 2.56 and St Dev = 2.5. ### Additional Information - The table appears to be part of a larger data analysis exercise, likely calculating standard deviation and investigating data spread using square roots of sums of squared deviations. - The note "50/8" likely indicates summing operations or mean calculations over a count of 8, but the exact interpretation may depend on prior context. This analysis provides insight into the distribution and variability of the given dataset, essential for statistical and educational purposes.
Transcribed Image Text:## Statistical Data Analysis ### Dataset and Calculations This table presents a dataset along with calculations for each data point, showing deviations from the mean and the squared deviations. #### Table Explanation | x | dev(x-2.56) | Dev^2 | |---|-------------|-------| | 0 | 0 - 2.56 = -2.56 | 6.55 | | 0 | 0 - 2.56 = -2.56 | 6.55 | | 1 | 1 - 2.56 = -1.56 | 2.4 | | 1 | 1 - 2.56 = -1.56 | 2.4 | | 2 | 2 - 2.56 = -0.56 | 0.3 | | 3 | 3 - 2.56 = 0.44 | 0.19 | | 3 | 3 - 2.56 = 0.44 | 0.19 | | 6 | 6 - 2.56 = 3.44 | 11.8 | | 7 | 7 - 2.56 = 4.44 | 19.7 | - **Total of x values**: 2.56 - **Sum of squared deviations**: 50.08 #### Calculations - **Mean (Average):** The mean of the dataset is given as 2.56. - **Sum of squares (Dev^2):** Total sums of the squared deviations is 50.08. - **Square root of the total squared deviations and IQR calculations:** - Square root of 6.25 isolated in the table. - Mean and standard deviation are shown as Mean = 2.56 and St Dev = 2.5. ### Additional Information - The table appears to be part of a larger data analysis exercise, likely calculating standard deviation and investigating data spread using square roots of sums of squared deviations. - The note "50/8" likely indicates summing operations or mean calculations over a count of 8, but the exact interpretation may depend on prior context. This analysis provides insight into the distribution and variability of the given dataset, essential for statistical and educational purposes.
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