Calculate the mass of antimony(III) lodide, Sblg, that can be produced by the reaction of 143 g of antimony, Sb (Z- 51), and 401 g of iodine. Also, find the mass in grams of the element that will be left. Iodine is a bluish-black lustrous solid at room conditions, as seen on the right. It readily sublimates -changes directly from solid to gas-to a blue- violet gas, as seen on the left. Mass of Sbl3 = 6. Mass of element left =
Calculate the mass of antimony(III) lodide, Sblg, that can be produced by the reaction of 143 g of antimony, Sb (Z- 51), and 401 g of iodine. Also, find the mass in grams of the element that will be left. Iodine is a bluish-black lustrous solid at room conditions, as seen on the right. It readily sublimates -changes directly from solid to gas-to a blue- violet gas, as seen on the left. Mass of Sbl3 = 6. Mass of element left =
Chemistry & Chemical Reactivity
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Chapter25: Nuclear Chemistry
Section25.8: Applications Of Nuclear Chemistry
Problem 1.4ACP: Calculate the molar mass (atomic weight) of naturally occurring uranium from the masses of the two...
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
Transcribed Image Text:Calculate the mass of antimony(III) lodide, Sbl3, that can be produced by the reaction of 143 g of antimony, Sb (Z- 51), and 401 g of iodine. Also, find the mass in grams of the element that will be left.
Iodine is a bluish-black
lustrous solid at room
conditions, as seen on the
right. It readily sublimates
-changes directly from
solid to gas-to a blue-
violet gas, as seen on the
left.
Mass of Sbl3 =
Mass of element left =
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