Calculate the mass density of diamond assuming that it is a close-packed structure of hard spheres with radii equal to half the carbon–carbon bond length of 154.45 pm. (b) The diamond lattice is in fact based on a face-centred cubic lattice but with two atoms per lattice point, such that the structure consists of two interpenetrating fcc lattices, one with its origin at (0,0,0) and the other with its origin at (1/4,1/4,1/4). The experimentally determined mass density is 3.516 g cm−3: can you explain the difference between this value and that in (a)?
Calculate the mass density of diamond assuming that it is a close-packed structure of hard spheres with radii equal to half the carbon–carbon bond length of 154.45 pm. (b) The diamond lattice is in fact based on a face-centred cubic lattice but with two atoms per lattice point, such that the structure consists of two interpenetrating fcc lattices, one with its origin at (0,0,0) and the other with its origin at (1/4,1/4,1/4). The experimentally determined mass density is 3.516 g cm−3: can you explain the difference between this value and that in (a)?
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter21: Structure And Bonding In Solids
Section: Chapter Questions
Problem 26P
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Calculate the mass density of diamond assuming that it is a close-packed structure of hard spheres with radii equal to half the carbon–carbon bond length of 154.45 pm. (b) The diamond lattice is in fact based on a face-centred cubic lattice but with two atoms per lattice point, such that the structure consists of two interpenetrating fcc lattices, one with its origin at (0,0,0) and the other with its origin at (1/4,1/4,1/4). The experimentally determined mass density is 3.516 g cm−3: can you explain the difference between this value and that in (a)?
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