Calculate the kVA output of a single phase transformer from the following data. Core height Distance between core centre (D) Diameter or circumscribing circle (d) Distance between core centre (D) Net iron area (A₁) π Area of circumscribing circle d² = 2.8 Distance between core centre D = 0.56 = 0.7 Window space factor Kw Frequency f 50 Hz Core flux density Bm = 1.2 Wb/m² = 0.27. - = 40 cm = 400 mm

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Calculate the kVA output of a single phase transformer from the following data.
Core height
Distance between core centre (D)
Diameter or circumscribing circle (d)
Distance between core centre (D)
Net iron area (A;)
Area of circumscribing circle d²
Window space factor Kw
= 2.8
Core flux density Bm
Distance between core centre D
= 0.56
= 0.7
= 0.27.
Frequency f = 50 Hz
= 1.2 Wb/m²
= 40 cm
= 400 mm
Transcribed Image Text:Calculate the kVA output of a single phase transformer from the following data. Core height Distance between core centre (D) Diameter or circumscribing circle (d) Distance between core centre (D) Net iron area (A;) Area of circumscribing circle d² Window space factor Kw = 2.8 Core flux density Bm Distance between core centre D = 0.56 = 0.7 = 0.27. Frequency f = 50 Hz = 1.2 Wb/m² = 40 cm = 400 mm
Expert Solution
Step 1

Distance between core centres D = 40 cm

= 400 mm

It is given that, Hw= 2.8

Hw= 2.8 x D

Height of window Hw = 2.8 x 40

= 112 cm

= 1120 mm

d It is given that d/D = 0.56 

d = 0.56 D

Diameter of circumscribing circle d = 0.56 × 40 =22.4 cm

= 224 mm

Width of window Ww= D - d

= 40 - 22.4

= 17.6 cm

= 176 mm

Area of window Aw= Hw x Ww

= 112 x 17.61970

= 1973.40 cm²

= 0.197 m²

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