Calculate the instantaneous value at for the voltage sine wave below. Determine the instantaneous value at 45° of a voltage sine wave that leads the reference by 10° (V₂ = 10 V). V (V) 10 8.66 0° 60° 90°
Calculate the instantaneous value at for the voltage sine wave below. Determine the instantaneous value at 45° of a voltage sine wave that leads the reference by 10° (V₂ = 10 V). V (V) 10 8.66 0° 60° 90°
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Transcribed Image Text:**Problem Statement:**
Calculate the instantaneous value at \( \theta \) for the voltage sine wave below.
Determine the instantaneous value at \( 45^\circ \) of a voltage sine wave that leads the reference by \( 10^\circ \) (\( V_p = 10 \, \text{V} \)).
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**Graph Explanation:**
The graph displays a voltage sine wave plotted against the angle \( \theta \) on the horizontal axis and the voltage \( V \) in volts (V) on the vertical axis.
Key features of the graph:
- The sine wave starts at \( 0^\circ \) and completes one-half of the cycle by \( 180^\circ \).
- The peak voltage (\( V_p \)) is indicated as 10 V.
- At \( 30^\circ \) (i.e., \( 45^\circ - 10^\circ \)), the voltage reaches approximately 8.66 V.
When evaluating the sine wave at \( 45^\circ \) leading by \( 10^\circ \):
- The corrected angle is \( 45^\circ - 10^\circ = 35^\circ \).
- The sine wave at \( 35^\circ \) shows an approximate instantaneous value of 8.66 V before reaching the peak value of 10 V at \( 60^\circ \).
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