Calculate the impedance Z(jw). At which frequency "w" the voltage of the source vit) and the current i(t) are in phase? (4) es cot at 24 www N() (1) 2H Su 146 0.5 F www

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IMPEDANCE FIND NETWORK( NEED NEAT HANDWRITTEN SOLUTION ONLY OTHERWISE DOWNVOTE).

**Problem Statement:**
Calculate the impedance \( Z(j\omega) \). At which frequency \( \omega \) the voltage of the source \( V(t) \) and the current \( i(t) \) are in phase?

**Diagram Explanation:**

The given circuit diagram consists of the following components:
1. An AC voltage source, represented as \( \cos(\omega t) \).
2. A resistor with a resistance of 2 ohms (\( 2\Omega \)).
3. Two inductors in series, with inductances of 2 henrys (\( 2H \)) and 1 henry (\( 1H \)), respectively.
4. A capacitor with a capacitance of 0.5 farads (\( 0.5F \)) in parallel with the 1-henry inductor.

The resulting current is denoted as \( i(t) \) and the voltage across the inductor-capacitor parallel combination is \( v(t) \).

**Circuit Analysis:**

1. **Series Components:**
   - Resistor: \( R = 2\Omega \)
   - Inductors: \( L_1 = 2H \) and \( L_2 = 1H \)

2. **Parallel Combination:**
   - Inductor: \( L = 1H \)
   - Capacitor: \( C = 0.5F \)

The impedance \( Z(j\omega) \) seen by the source can be found by calculating the impedance of each component and combining them accordingly.

- The impedance of an inductor \( L \) at an angular frequency \( \omega \) is \( j\omega L \).
- The impedance of a capacitor \( C \) at an angular frequency \( \omega \) is \( \frac{1}{j\omega C} \).

Given these definitions, the total impedance can be calculated.
Transcribed Image Text:**Problem Statement:** Calculate the impedance \( Z(j\omega) \). At which frequency \( \omega \) the voltage of the source \( V(t) \) and the current \( i(t) \) are in phase? **Diagram Explanation:** The given circuit diagram consists of the following components: 1. An AC voltage source, represented as \( \cos(\omega t) \). 2. A resistor with a resistance of 2 ohms (\( 2\Omega \)). 3. Two inductors in series, with inductances of 2 henrys (\( 2H \)) and 1 henry (\( 1H \)), respectively. 4. A capacitor with a capacitance of 0.5 farads (\( 0.5F \)) in parallel with the 1-henry inductor. The resulting current is denoted as \( i(t) \) and the voltage across the inductor-capacitor parallel combination is \( v(t) \). **Circuit Analysis:** 1. **Series Components:** - Resistor: \( R = 2\Omega \) - Inductors: \( L_1 = 2H \) and \( L_2 = 1H \) 2. **Parallel Combination:** - Inductor: \( L = 1H \) - Capacitor: \( C = 0.5F \) The impedance \( Z(j\omega) \) seen by the source can be found by calculating the impedance of each component and combining them accordingly. - The impedance of an inductor \( L \) at an angular frequency \( \omega \) is \( j\omega L \). - The impedance of a capacitor \( C \) at an angular frequency \( \omega \) is \( \frac{1}{j\omega C} \). Given these definitions, the total impedance can be calculated.
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