Calculate the heat released (kJ) in the reaction of 3.50 g of acetylene (C2H2) and excess hydrogen gas to form ethane gas: C2H2(g) + 2H2(g) – C2H6(g) Given: 2C2H2(g) + 502(g) → 4CO2(g) + 2H20(g) AH =-2320 kJ/mol 2C2H6(g) + 702(g) → 4CO2(g) + 6H20(g) AH = -3040 kJ/mol 2H2(g) + O2(g) → 2H20(g) AH = -572 kJ/mol

Calculate the heat released (kJ) in the reaction of 3.50 g of acetylene (C2H2) and excess hydrogen gas to form ethane gas: C2H2(g) + 2H2(g) – C2H6(g) Given: 2C2H2(g) + 502(g) → 4CO2(g) + 2H20(g) AH =-2320 kJ/mol 2C2H6(g) + 702(g) → 4CO2(g) + 6H20(g) AH = -3040 kJ/mol 2H2(g) + O2(g) → 2H20(g) AH = -572 kJ/mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

chem 7

Calculate the heat released (kJ) in the reaction of 3.50 g of acetylene (C2H2) and excess hydrogen gas to form ethane gas:
C2H2(g) + 2H2(g) – C2H6(g)
Given:
2C2H2(g) + 502(g) → 4CO2(g) + 2H20(g) AH =-2320 kJ/mol
2C2H6(g) + 702(g) → 4CO2(g) + 6H20(g) AH = -3040 kJ/mol
2H2(g) + O2(g) → 2H20(g) AH = -572 kJ/mol

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