Calculate the heat of reaction (in J).     qrxn = ×10 J Enter your answer in scientific notation.

Q: When 151.0 mL of water at 26.0°C is mixed with 46.0 mL of water at 85.0°C, what is the final…

A: Aplly calorimetry principle Q= mc∆T  Heat flow from high Temperature to low temperature.

Q: 1.00 kg of Cu at 42 degrees Celcius is placed into 100. g of water at 15.0 degrees Celcius. The…

A: Loss of heat by the metal = Gain of heat by the water.

Q: In the laboratory a student finds that it takes 173 Joules to increase the temperature of 11.1 grams…

A: Given heat is 173 j

Q: If 1001 J of heat is available, what is the mass in grams of iron (specific heat = 0.450 J/g･°C)…

A: Given Heat ( Q ) = 1001 Joule  Specific heat ( s ) = 0.450 Joule/gram℃  Initial temperature ( T1 ) =…

Q: A 131.9 g piece of copper (specific heat 0.380 J/g･°C) is heated and then placed into 400.0 g of…

A: Mass of Cu = 131.9 g = MCuSpecific heat of Cu = CCu = 0.38 J/g°CIntial temperature of Cu = TcMass of…

Q: A 135.1 g piece of copper (specific heat 0.380 J/g･ °C) is heated and then placed into 400.0 g of…

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Q: A 89.5 g piece of copper (specific heat 0.380 J/g･°C) is heated and then placed into 400.0 g of…

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Q: A 3006 mg sample of magnesium metal is heated from 5.500 °C to 15.490 °C. This process requires…

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Q: 261.28 mL of 4.0°C water is heated until its temperature is 48.24°C. If the specific heat of water…

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Q: A 167.8 g piece of iron initially at 25.0 Celsius, absorbs 10943 J of energy. What will the final…

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Q: the energy needed to heat 12.6 g of silver from 112 °C to 275 °C

A:

Q: A 93.1 g piece of copper (specific heat 0.380 J/g･°C) is heated and then placed into 400.0 g of…

A: Q=M S ∆T  Q=heat M=mass S=specific heat ∆T=change in temperature

Q: An unknown substance weighs 450.0 grams and had a temperature change from 130 degrees celsius to 80…

A: The mass of the solid substance is m = 450.0 g. The initial temperature is Ti = 130oC. The final…

Q: If 10.27 kJ of heat is given off when 51.93 g of unknown acid condenses from vapor to liquid, what…

A: Condensation is a process of conversion of vapor to liquid. Enthalpy of condensation is the enthalpy…

Q: A 147.5 g piece of copper (specific heat 0.380 J/g･°C) is heated and then placed into 400.0 g of…

A: Answer:- This question is answered by using the simple concept of calorimetry which states that heat…

Q: A 101.9 g piece of copper (specific heat 0.380 J/g･°C) is heated and then placed into 400.0 g of…

A: Given Mass of cu = 101.9 g Mass of water = 400 g Initial temperature of water = 20.7 oC Final…

Q: You have a piece of iron, the specific heat of iron, the specific heat of iron is 0.449 J/g °C and…

A: Specific heat :-  The amount of heat required to rise the temperature of one gram of a substance…

Q: A 87.9 g piece of copper (specific heat 0.380 J/g･°C) is heated and then placed into 400.0 g of…

A: Please find the solution in image attached below.

Q: A chemical substance has a specific heat of 0.897 J/g-ºC. If an unknown mass of this substance is…

A: Answer:- This question is answered by using the simple concept of calculation of heat using the…

Q: The specific heat of a certain type of metal is 0.128 J/(g*c). What is the final tempature if 305J…

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Q: A 122.7 g piece of copper (specific heat 0.380 J/g･°C) is heated and then placed into 400.0 g of…

A: The mass of copper added to 400.0 g of water is 122.7 g. The initial and final temperature of water…

Q: If 701 J of heat is available, what is the mass in grams of iron (specific heat = 0.450 J/g･°C) that…

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Q: If 801 J of heat is available, what is the mass in grams of iron (specific heat = 0.450 J/g•°C) that…

A: Given,  specific heat = 0.450 J/g.oC heat = 801 J , mass = ? , ∆T= 120°C - 22.5°C = 97.5°C

Q: A 145.9 g piece of copper (specific heat 0.380 J/g･°C) is heated and then placed into 400.0 g of…

A: Mass of water(m1) = 400.0 g Change in Temperature (ΔT1) = 22.2-20.7 °C = 1.5 °C Mass of Copper (m2)…

Q: A 130.3 g piece of copper (specific heat 0.38 J/g･°C) is heated and then placed into 400.0 g of…

A: Given : Mass of water = 400.0 g Mass of metal = 130.3 g Initial temperature of water = 20.7 oC Final…

Q: If 801 J of heat is available, what is the mass in grams of iron (specific heat = 0.45 J/g･°C) that…

A: Q = heat =801 J ΔT = change in temperature = (120 - 22.5) = 97.5 oC c = Specific heat = 0.45 J/goC…

Q: Suppose you mix 23.1 g of water at 80.3°C with 44.8 g of water at 25.4°C in an insulated cup. What…

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Q: Exactly 122 J will raise the temperature of 11.96 g of a metal from 20.0 °C to 65.0 °C. What is the…

A: Q = ms∆T Q = heat transfer m = mass  s = specific heat ∆T = temperature difference

Q: 50.00 grams of water in a calorimeter at 22.9 degrees Celsius. At equilibrium the temperature of the…

A: Initial temperature of water (T1) = 22.9 °C Final temperature of water T2= 37.6 °C So, Change in…

Q: Using the following reactions, calculate the heat of the first reaction. Note: all three enthalpies…

A: The enthalpy change is a state function and the Hess law states that the change of enthalpy in a…

Q: Suppose you heat a metal object with a massive 31.6 G to 95.5 C and transfer it to a calorimeter…

A: Given : Mass of water = 100.0 g Mass of metal = 31.6 g Initial temperature of water = 17.8 oC Final…

Q: A 133.5 g piece of copper (specific heat 0.380 J/g･ °C) is heated and then placed into 400.0 g of…

A: FINAL ANSWER:The initial temperature of Copper was 71.68 0C. The detailed solution is given below.…

Q: what is the mass in grams of iron

A:

Q: 107 g of Cu at 108.9°C was added to 258.7 g of H2O at 17.4°C.  If the specific heat of copper is…

A: Copper Mass m = 107 g C = Specific heat of copper = 0.389 J/g.°C Initial temperature Ti = 108.9°C…

Q: ,11) [References) Use the References to access important values if needed for this question. In the…

A:

Q: When 156.0 mL of water at 26.0°C is mixed with 86.0 mL of water at 85.0°C, what is the final…

A: Convert the given mL of water into mass.Given, density of water = 1.00 g/mL

Q: If 801 J of heat is available, what is the mass in grams of iron (specific heat = 0.450 J/g･°C) that…

A: Given data : Heat (q) = 801 J Specific heat (C) = 0.450 J/g.°C Initial temperature (Ti) = 22.5 °C…

Q: If 701 J of heat is available, what is the mass in grams of iron (specific heat = 0.450 J/g･°C) that…

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Q: Calculate the heat change in kilocalories for freezing 265 g of water at 0 degrees Celsius.

A: Mass of water = 265 g