Calculate the freezing-point depression and osmotic pressure in torr at 25°C for an aqueous solution of 3.1 g/L of a protein (molar mass = 9.0x104 g/mol) if the density of the solution is 1.0 g/cm³. (Use the data in the Boiling-Point Elevation (K) and Freezing-Point Depression (K₂) Constants table.) freezing-point depression °℃ osmotic pressure torr

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Calculate the freezing-point depression and osmotic pressure in torr at 25°C for an aqueous solution of 3.1 g/L of a protein (molar mass = 9.0×104 g/mol) if the density of the solution is 1.0 g/cm³. (Use the data in
the Boiling-Point Elevation (K) and Freezing-Point Depression (K₁) Constants table.)
°C
freezing-point depression
osmotic pressure
torr
Transcribed Image Text:Calculate the freezing-point depression and osmotic pressure in torr at 25°C for an aqueous solution of 3.1 g/L of a protein (molar mass = 9.0×104 g/mol) if the density of the solution is 1.0 g/cm³. (Use the data in the Boiling-Point Elevation (K) and Freezing-Point Depression (K₁) Constants table.) °C freezing-point depression osmotic pressure torr
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Step 1: Defining colligative properties

Answer:

Properties that depend on the number of solute particles present in the solution are called as colligative properties. Freezing point depression and osmotic pressure are colligative properties.

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