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Calculate the forces on the supports in the internally supported excavation system given in the figure. horizontal distance between supports - 3m Annual lateral pressure=0.65YHK 1.0 m A kum 2.0 m -30° B. r-17.1 kN/m? 2.0 m 1.5 m yanal basnç=0.65YHK. a) PA=201 kN, PB-98 kN, PB-195 kN b) O PA=148 kN. PB=97 kN, PB-235 kN c) PA=155 kN, PB=210 kN, PB=92 kN PA=145 kN, PB=75 kN, PB=193 kN PA=161 kN, PB=85 kN, PB=219 kN

Calculate the forces on the supports in the internally supported excavation system given in the figure. horizontal distance between supports - 3m Annual lateral pressure=0.65YHK 1.0 m A kum 2.0 m -30° B. r-17.1 kN/m? 2.0 m 1.5 m yanal basnç=0.65YHK. a) PA=201 kN, PB-98 kN, PB-195 kN b) O PA=148 kN. PB=97 kN, PB-235 kN c) PA=155 kN, PB=210 kN, PB=92 kN PA=145 kN, PB=75 kN, PB=193 kN PA=161 kN, PB=85 kN, PB=219 kN

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Calculate the forces on the supports in the internally supported excavation system given in the figure. horizontal distance between supports = 3m Annual lateral pressure=0.65YHK 1.0 m A kum 2.0 m 0=30° =17.1 kN/m? B. 2.0 m 1.5 m yanal basınç=0.65YHK, a) PA=201 kN, PB=98 kN, PB=195 kN b) PA=148 kN. PB=97 kN. PB=235 kN C) PA=155 kN, PB=210 kN, PB=92 kN PA=145 kN, PB=75 kN, PB=193 kN e) PA=161 kN, PB=85 kN, PB=219 kN
Transcribed Image Text:Calculate the forces on the supports in the internally supported excavation system given in the figure. horizontal distance between supports = 3m Annual lateral pressure=0.65YHK 1.0 m A kum 2.0 m 0=30° =17.1 kN/m? B. 2.0 m 1.5 m yanal basınç=0.65YHK, a) PA=201 kN, PB=98 kN, PB=195 kN b) PA=148 kN. PB=97 kN. PB=235 kN C) PA=155 kN, PB=210 kN, PB=92 kN PA=145 kN, PB=75 kN, PB=193 kN e) PA=161 kN, PB=85 kN, PB=219 kN
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