Calculate the force of gravity that Earth (mass 6.0x1024kg) and the Sun exert on each other (Sun's mass=2x10³0kg, distance =1.5x10¹¹m)
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- The earth is 150 × 10^9 m from the Sun. Earth and Sun masses are 5.97 × 10)^24 ?? and 1.99 × 10^30 ??, respectively. (a) Find the gravitational attraction between the Earth and the Sun. (b) Find the orbital period of the Earth around the Sun based on these numbers.A distant planet with a mass of (2.800x10^26) has a moon with a mass of (9.0000x10^23). The distance between the planet and the moon is (8.8000x10^11). What is the gravitational force between the two objects? Note: Your answer is assumed to be reduced to the highest power possible.The gas-giant planet Rom (mass 5.7⨯1026 kg) goes around the star Galla (mass 2.0⨯1030 kg) in a circular orbit. If the orbital radius of Rom is 2.5×1011 m … Note: G = 6.67⨯10-11 N·m2/kg2 i) What is the gravitational force of Rom on Galla?
- Determine the gravitational field at mass A. The radius of masses A and C is 50 cm while the radius of mass B is 75 cm.Three uniform spheres of masses m₁ = 2.50 kg, m₂ = 4.00 kg, and m3 = 5.50 kg are placed at the corners of a right triangle (see figure below). Calculate the resultant gravitational force on the object of mass m₂, assuming the spheres are isolated from the rest of the Universe. 10-11 N (0, 3.00) m (-4.00, 0) m M₂ 0 m₁ F12 m₂During a solar eclipse, the Moon is positioned directly between Earth and the Sun. The masses of the Sun, Earth, and the Moon are 1.99 × 10³0 kg, 5.98 × 1024 kg, and 7.36 × 1022 kg, respectively. The Moon's mean distance from Earth is 3.84 × 108 m, and Earth's mean distance from the Sun is 1.50 × 10¹¹ m. The gravitational constant is G = 6.67 × 10-¹1 N-m²/kg². Find the magnitude F of the net gravitational force acting on the Moon during the solar eclipse due to both Earth and the Sun. F = What is the direction of this force? toward Earth toward Venus toward the Sun elsewhere N
- A 4.00 x 10^8 kg mass and 5.00 x 10^8 kg mass are separated by a distance of 2.0 km. What is the gravitational force of attraction between the masses?Two objects attract each other with a gravitational force of magnitude 1.01 If the total mass of the two objects is 5.12 kg, what is the mass of each? 10^-8 N when separated by 19.4 cm. heavier mass: kg lighter mass : kgLet planet A have a mass of 5.44 x 1045 kg and planet B have a mass of 2.77 x 1033 If they are attracted by a gravitational force of 6.59 x 103 N, how far apart are their centers of mass
- Two objects attract each other with a gravitational force of magnitude 9.00 10-9 N when separated by 19.9 cm. If the total mass of the objects is 5.08 kg, what is the mass of each? heavier mass answer in ___kg lighter mass answer in ___kgObjects with masses of 220 kg and 410 kg are separated by 0.415 m. A 58.3 kg mass is placed midway between them. Find the magnitude of the net gravitational force exerted by the two larger masses on the 58.3 kg mass. The value of the universal gravi- tational constant is 6.672 × 10−11 N · m2/kg2. Answer in units of N. Leaving the distance between the 220 kg and the 410 kg masses fixed, at what distance from the 410 kg mass (other than infinitely remote ones) does the 58.3 kg mass experience a net force of zero? Answer in units of m.A satellite is orbiting the earth in low orbit (160 km above the surface of the earth). If the universal gravitational constant is 6.67 x 10^-11 m^3/kg x s^2 the mass of the earth is 5.972 x 10^24 kg and the radius of the earth is 6371 km, what speed must the satellite travel in order to maintain the low earth orbit?