Calculate the expected absorbance of a 20mg/L. solution of potassium permanganate at 525m. Note the Mt of potassium permanganate is 158 g/mol and assume the molar absorptivity at 525mm is 2100 M~1 cm*1. Round answer to 2
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- g 2.png Average absorbance, .129 +0.128 +0.127)/3 = 0.128 Chrome Concentration of Females of Fe volume Q Molarity of Fe(NO₂)) = 0.2M Volume of Fe(NO₂)); = 5.00mL Moles of Fe³+= Molarity x Molarity x volume(L) Moles of Fe³* = 0.2M x 0.0054 = 10³mole 10-mole 500 x 10-3=0.002M [Fe³+] = [SCN¯] = X = ✪ [Fe³] = 0.002mol/L nknown concentrations to determine [FeSCN]at equilibrium in solution 8: Y = 4290X - 0.068 72% (0.127 + 0.068) 4290 0.127=4290X - 0.068 25ml Fe³+ x 0.002 mol/L-¹ 100mL 100% = 4.5 x 10-5mol/L 20ml SCN X 0.002 mol/L-¹ 100mL = 5.00 x 10^4 mol/L^-1 = 4.00 x 10 mol/L-1 W Flask 8 Flask 9 Flask 10 Flask 11 3.png 4.png Part 3: Q8 Flask 8 Flask 9 Flask 10 Flask 11 Part 3: 09 Flask 8 Flask 9 Flask 10 Flask 11 [Fe³+ (mol/L) 5.00 x 10-4 5.00 x 10-4 5.00 x 10-4 5.00 x 10-4 Average absorbance 0.127 0.166 0.222 69% 0.308 100% [FESCN¹ (mol/L) 4.5 x 10- 5.4 x 10 6.76 x 10-5 8.76 x 10- [SCN (mol/L) 4.00 x 10-4 4 x 10-4 7 x 10-4 1x 10-³ 3 7.png Place the results from calculations 9 and 10 into…So Please don't provide the handwriting solution45.0 mL of an unknown FeCl3 solution is diluted to a total volume of 230.0 mL. The diluted FeCl3 solution measured an absorbance of 0.223. Calculate the molarity of the undiluted unknown FeCl3 solution if the molar extinction coefficient is 230.0 M-1⋅cm-1 and a path length of 1.00 cm. Group of answer choices 0.000190 M 0.00496 M 0.00593 M 10.0 M 0.00399 M
- I did an experiment: Molar concentration of Fe (NO3)3=.002 Molar concentration of NaSCN= .002 On my 1st trial: Volume of Fe(NO3)3 = 5 mL Moles of Fe3+, initial (mol) = 1 x 10-5 Volume of NaSCN (mL)= 1 mL Moles of SCN-,initial (mol)= 2 x 10-6 Absorbance was .08 Now trying to find Calculation of Kc I already found [FeNCS2+] equilibrium, from calibration curve (mol/L)= 2.25 x 10-5 Now I need to know: 1. moles FeNCS2+ at equilibrium (10mL) (mol) 2. moles Fe3+, reacted (mol) 3. moles Fe3+, equilibrium (mol) 4. [Fe3+] equilibrium, unreacted, 10 mL (mol/L) 5. moles SCN-, reacted (mol) 6. Moles SCN-, equilibrium (mol) 7. [SCN-] equilibrium (unreacted) 10 mL (mol/L) Feel free to just give me the formula to find these. Or to charge me 2 or 3 questions if I asked too much. Thank you!!!!!!Q3) A solution of Tryptophan has an absorbance at 280 nm of 0.25 in a 0.5 cm length cuvette. Given the absorbance coefficient of Tryptophan is 6.4 × 103 L Mol-1 cm-1. What is the concentration of solution?CHOCIS Small! X= 5.92×10-5 = [ht] plt 9) Calculate the pH of a solution that contains 1.00 MHCN (K. = 6.2 x 10-¹0) and 5.00 M HNO₂ (K₁ = 4.0 x 10). Also calculate the concentration of cyanide ion (CN) in this solution at equilibrium. ignore the HCN - the concentraction is low & Ka + is 50 Solve using a standard ICE table for tril, only
- Caffeine (C8H10O2N4 • H2O) has an absorbance of 0.510 at 272 nm and 1 cm optical path in1 mg / 100 mL concentration solutions. A 2.5 g sample of soluble coffee is diluted withwater to 500 mL. Take 250 mL, add 25.0 mL of 0.1 N H2SO4 and dilute it to 500 mL. Theabsorbance at 272 nm resulting in 0.415. A) Calculate the grams of caffeine per kg of soluble coffee in the sample. Themolar mass of caffeine is 212 g / mol.Caffeine, C8H10O2N4 H2O (MW = 212.2 g/mol) has been shown to have an average absorbance of 0.644 for a concentration of 1.783 mg per 100 mL at 272 nm. A sample of 3.658 g of a soluble coffee product was mixed with water to a volume of 500 mL and a 25 mL aliquot was transferred to a flask containing 25 mL of 0.1 M H2SO4. This was subjected to the prescribed clarification treatment and made up to 500 mL. A portion of this treated solution showed an absorbance of 0.666 at 272 nm. Assumbe b = 1.0 cm. Calculate the % caffeine (w/w) in the sample.4
- What is the concentration of a solution with an absorbance of 0.23 a.u. in ppm when y=45.3509y45.0 mL of an unknown FeCl3 solution is diluted to a total volume of 230.0 mL. The diluted FeCl3 solution measured an absorbance of 0.223. Calculate the molarity of the undiluted unknown FeCl3 solution if the molar extinction coefficient is 230.0 M-1⋅cm-1 and a path length of 1.00 cm.What is the molar absorptivity and concentration of caffeic acid? Molar mass= 180g/mol the cuvette= 1cm absorbance= 1.98 Started by adding 0.0019g of caffeic acid in 25 mL methanol. This solution was diluted with methanol in 1:100mL, then again in 1:10 dilution.